The answer will be 21u^6v^8
Answer:
I don't if this is right but is the 629
Step-by-step explanation:
Answer:
a) P(t>3)=0.30
b) P(t>10|t>9)=0.67
Step-by-step explanation:
We have a repair time modeled as an exponentially random variable, with mean 1/0.4=2.5 hours.
The parameter λ of the exponential distribution is the inverse of the mean, so its λ=0.4 h^-1.
The probabity that a repair time exceeds k hours can be written as:
(a) the probability that a repair time exceeds 3 hours?
(b) the conditional probability that a repair takes at least 10 hours, given that it takes more than 9 hours?
The exponential distribution has a memoryless property, in which the probabilities of future events are not dependant of past events.
In this case, the conditional probability that a repair takes at least 10 hours, given that it takes more than 9 hours is equal to the probability that a repair takes at least (10-9)=1 hour.
Answer:
The solution can be defined as follows:
Step-by-step explanation:
They also have a significant outcome in our instance. Its value of F is 1.773, with such a p-value of 0.212 achieved meaning (which is greater than the .05 alpha level). It means that the press with different levels of stress of the stress variable may not differentiate objectively.
Even so, we still do not know which one of the multiple mechanisms is significant. They realize the diff. To do just that, the results of the Tukey HSD test should be regarded.
HSD Tukey
Looking at the Multiple Correlations table below, you will see that mean values were created for the standard deviation among pairs of various stress varying concentrations (High - Low; High - Medium )
This can be seen on one-way ANOVA(1.773, p=.212), there's no statistically significant difference between the groups. A Tukey post hoc study has observed that the increase among medium and high stress is statistically significant, as well as the difference among low, medium, and high stress is important.
