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3 years ago

PLEASE HELP!! 50 POINTS!!

1 answer:

3 0

They are saying to write a quadratic that can be factored so you can start with factors and then expand it like say:

(x+1)(x+2) are arbitrary factors, then the expansion is

x^2+3x+2 which we know can then be factored to what we started with...

In general to factor a quadratic of the form ax^2+bx+c, you need to find two values, j and k, which satisfy two conditions:

ac=jk=2 and b=j+k=3, so j and k must be 1 and 2

Then you replace bx with jx and kx in the original equation to get:

x^2+x+2x+2 now factor 1st and 2nd pair of terms...

x(x+1)+2(x+1) which is equal to

(x+1)(x+2)

....

If j and k are integers, the above method is the quickest and easiest.

Next in line of preference is completing the square if there are fractional numbers in the original equation.

And if there are very difficult decimals or fractions it is best to just use the quadratic formula (which is derived from completing the square)

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Step-by-step explanation:

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4 years ago

Make a Factor Tree with these numbers<br><br><br> 1,000 256 288 192 999

4vir4ik [10]

Answer:

1000256288192999 is too big.

Step-by-step explanation:

Ex.: 6, 9, 26, 256, etc.

This calculator accepts big numbers up to 100,000 or more.

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1000256288192999 is too big.

Factor tree for 1000256288192999

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3 years ago

The square root of 9 times x to the 6th power

ololo11 [35]

Answer:

531,441

Step-by-step explanation:

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3 years ago

Read 2 more answers

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Answer:$87.69

Step-by-step explanation:

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3 years ago

I'm giving brainliest to the most helpful answer. For 50 points:

Alenkinab [10]

Answer:

1) $\displaystyle\frac{5}{18}\approx27.78\%$

2) $\displaystyle\frac{4}{7}\approx57.14\%$

3) $\displaystyle \frac{13}{16}=81.25\%$

Step-by-step explanation:

We are given a two-way frequency table. Using the table, we will determine the probability for each case.

Question 1)

P(A Student With A Part Time Job Without A Car)

Using the first column, the total number of students that have a part time job is 78+30=108.

Likewise, using the first column, we can see that out of those 108 students, 30 do not have a car.

Hence, the probability that a student with a part time job without a car is:

$\displaystyle P=\frac{30}{108}=\frac{5}{18}\approx27.78\%$

Question 2)

P(No Car | Does Not Have A Part Time Job)

Remember that the vertical line means conditional probability.

So, we want the probability of a student having no car given that they do not have a part time job.

Using the second column, we can see that the total number of students that do not have a part time job is 18+24=42.

Likewise, using the second column, 24 do not have a car.

Hence, the probability that a student with a part time job without a car is:

$\displaystyle P=\frac{24}{42}=\frac{4}{7}\approx57.14\%$

Question 3)

P(Part Time Job | Car)

So, we want to probability of a student having a part time job given that they have a car.

Using the first row, the total students that have a car is 78+18=96.

And of those 96 students, 78 have a part time job.

Hence, the probability that a student with a car has a part time job is given by:

$\displaystyle P=\frac{78}{96}=\frac{13}{16}=81.25\%$

4 0

3 years ago