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Katyanochek1 [597]
3 years ago
5

PLEASE HELP!! 50 POINTS!!

Mathematics
1 answer:
salantis [7]3 years ago
3 0
They are saying to write a quadratic that can be factored so you can start with factors and then expand it like say:

(x+1)(x+2)  are arbitrary factors, then the expansion is

x^2+3x+2  which we know can then be factored to what we started with...

In general to factor a quadratic of the form ax^2+bx+c, you need to find two values, j and k, which satisfy two conditions:

ac=jk=2 and b=j+k=3, so j and k must be 1 and 2

Then you replace bx with jx and kx in the original equation to get:

x^2+x+2x+2  now factor 1st and 2nd pair of terms...

x(x+1)+2(x+1) which is equal to

(x+1)(x+2)

....

If j and k are integers, the above method is the quickest and easiest.

Next in line of preference is completing the square if there are fractional numbers in the original equation.

And if there are very difficult decimals or fractions it is best to just use the quadratic formula (which is derived from completing the square)
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Answer:

a. Discrete probability distribution, frequent rider club, 0.65 of 20

b. 13

c. $60

d. $57.50

Step-by-step explanation:

a. X follows a discrete probability distribution because it involves discrete random variables which have probability mass function and frequency.

f(x) =0.65 of 20 passengers

b. if 0.65 0f 20 passengers are frequent riders,

then, the frequent riders will be 13 passengers

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the total number of passengers given tickets is 20 and the price for each is $3. thus, making the parameters to be price and number of passengers.

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