1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Katyanochek1 [597]
3 years ago
5

PLEASE HELP!! 50 POINTS!!

Mathematics
1 answer:
salantis [7]3 years ago
3 0
They are saying to write a quadratic that can be factored so you can start with factors and then expand it like say:

(x+1)(x+2)  are arbitrary factors, then the expansion is

x^2+3x+2  which we know can then be factored to what we started with...

In general to factor a quadratic of the form ax^2+bx+c, you need to find two values, j and k, which satisfy two conditions:

ac=jk=2 and b=j+k=3, so j and k must be 1 and 2

Then you replace bx with jx and kx in the original equation to get:

x^2+x+2x+2  now factor 1st and 2nd pair of terms...

x(x+1)+2(x+1) which is equal to

(x+1)(x+2)

....

If j and k are integers, the above method is the quickest and easiest.

Next in line of preference is completing the square if there are fractional numbers in the original equation.

And if there are very difficult decimals or fractions it is best to just use the quadratic formula (which is derived from completing the square)
You might be interested in
HELP PLEASE!!
shutvik [7]

Answer:

6.5 x 10^6 To answer this question, you need to divide the mass of the sun by the mass of mercury. So 2.13525 x 10^30 / 3.285 x 10^23 = ? To do the division, divide the mantissas in the normal fashion 2.13525 / 3.285 = 0.65 And subtract the exponents. 30 - 23 = 7 So you get 0.65 x 10^7 Unless the mantissa is zero, the mantissa must be greater than or equal to 0 and less than 10. So multiply the mantissa by 10 and then subtract 1 from the exponent, giving 6.5 x 10^6 So the sun is 6.5 x 10^6 times as massive as mercury.

:}

8 0
3 years ago
Read 2 more answers
Find the common difference of the arithmetic sequence -6,2, 10, ​
Yuki888 [10]

Answer:

the common ratio is +8

10 - 2 = 8

2 - (-6) = 8

8 0
3 years ago
Micah is preparing for a piano recital. He practices for 50 minutes on Monday and 90 minutes on Wensday
SCORPION-xisa [38]

Answer:

She increased 80% the practise time

Step-by-step explanation:

The question is incomplete, the following is missing:

<em>by how much did she increase the time she practised each day? </em>

From Monday to Wednesday she increased 90 - 50 = 40 minutes  the practise time.

To compute the increment as a percentage use: increment/reference *100

In this case, that is: 40/50*100 = 80%, where 50 minutes is taken as a reference.

6 0
3 years ago
Read 2 more answers
What is the product of 73 and 4.4 x 10^6 expressed in scientific notation?​
Dima020 [189]

Answer: 7.3 x 10^1 & 4400000.

Step-by-step explanation: Count the place holders and just add zeros to the exponential amount.

7 0
3 years ago
6z+10=-2<br><br> pls answer' <br> i willmarke brainlest
Blizzard [7]

Answer:

Step-by-step explanation: 6z=-2-10

6z= -12

z=-12/6

then z= -2

5 0
3 years ago
Read 2 more answers
Other questions:
  • Which expression has a negative value?
    12·2 answers
  • If you had 26/12 dollars how much money would that be in dollars and cents
    12·1 answer
  • Emma is a sales clerk at a bicycle shop. She is paid $8.50 per hour for 32 hours workweek plus a commission of 6% of sales. In o
    10·1 answer
  • Write in point slope form of the line that passes through the points (3,-1) and (6,-2)
    9·1 answer
  • HELP ME PLEASEEE this is past due
    9·1 answer
  • I need help in this zzzzzzz
    12·1 answer
  • X varies directly with<br> y. If x = 60 when<br> y = 75. find x when<br> y = 32.
    7·2 answers
  • Consider the Function g(x) = 1/x+3 — 4
    11·1 answer
  • WILL AWARD BRAINLIEST PLS HELP!!
    13·2 answers
  • The surface area of a sphere with radius R can be calculated using the formula S=4pi*r^2. Write a formula showing r's dependence
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!