<span>THE GIVEN QUESTION;
7x -3(4x-8) < 6x +12 - 9x
THE GIVEN INTERVAL OF X IS FROM [4,8] SO THE VALUE OF X ={4,5,6,7,8}
THE GIVEN QUESTION CAN BE EVALUATED TO
7x - 12x+ 24 < 12 - 3x
-5x + 24 < 12 - 3x //USING BODMAS RULE
NOW SUBSTITUTING THE VALUE OF X:
1) X=4 SOL: 4<0
2) X=5 SOL: -1<-3
3) X=6 SOL: -6<-6
4) X=7 SOL: -11<-9
5) X=8 SOL: -16<-12
HENCE THE VALUE OF X=7,8 SATISFY THE GIVEN INEQUALITY</span>
Answer:
6^-8 or 1/ 6^8
Step-by-step explanation:
When there is a fraction with the same base, then subtract the exponent of the denominator from the exponent of the numerator.
6^-3 / 6^5 = 6^(-3-5) = 6^-8
You start order of operations (PEMDAS)
You multiple left to right and lastly subtract.
12-2=10
