Question

help asap show work | a gas with a volume of 13L at a pressure of 197 kPA is allowed to expand to a volume of 23L. what is the pressure of the container if the temperature remains constant

Answer 1

Answer:

111 kPa

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the new pressure

$P_2 = \frac{P_1V_1}{V_2}$

We have

$P_2 = \frac{13 \times 197000}{23} = \frac{2561000}{23} \\ = 111347.826...$

We have the final answer as

111 kPa

Hope this helps you