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jeka94
2 years ago
10

Describe how you could show by adding aqueous sodium hydroxide and aqueous ammonia that a solution contained zinc ions.

Chemistry
1 answer:
Blababa [14]2 years ago
3 0

Answer:

Learning Task 3. Solving word problems involving multiplication of deci-

the

A cstep in solving word problems. Do these in your notebook. ),

1. A clerk is paid P 45.25 per hour for 40 hours a week, 1.50 times the

regular rate for overtime and double the rate for a holiday. How much

holiday?

2. fofkmputer programmer earns a regular hourly rate of P50.00. If he

worked 42.75 hours in a week, how much did he earn?

3. Arthur earns P1350.00 a day. He sets aside 0.10 of this for savings.

How much does he save in a month?

4. Mr. Fernandez has a monthly pay of P 5,450. The tax deducted from

year?

5. Dianne works 2.5 hours a day from Monday to Friday and 3.75 hours

his a

on Saturday. If he is paid P25.00 per hour, how much does he earn in

a

week?

Explanation:

Learning Task 3. Solving word problems involving multiplication of deci-

the

A cstep in solving word problems. Do these in your notebook. ),

1. A clerk is paid P 45.25 per hour for 40 hours a week, 1.50 times the

regular rate for overtime and double the rate for a holiday. How much

holiday?

2. fofkmputer programmer earns a regular hourly rate of P50.00. If he

worked 42.75 hours in a week, how much did he earn?

3. Arthur earns P1350.00 a day. He sets aside 0.10 of this for savings.

How much does he save in a month?

4. Mr. Fernandez has a monthly pay of P 5,450. The tax deducted from

year?

5. Dianne works 2.5 hours a day from Monday to Friday and 3.75 hours

his a

on Saturday. If he is paid P25.00 per hour, how much does he earn in

a

week?

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If 21.00 mL of a 0.68 M solution of C6H5NH2 required 6.60 mL of the strong acid to completely neutralize the solution, what was
Andru [333]

Answer:

pH = 2.46

Explanation:

Hello there!

In this case, since this neutralization reaction may be assumed to occur in a 1:1 mole ratio between the base and the strong acid, it is possible to write the following moles and volume-concentrations relationship for the equivalence point:

n_{acid}=n_{base}=n_{salt}

Whereas the moles of the salt are computed as shown below:

n_{salt}=0.021L*0.68mol/L=0.01428mol

So we can divide those moles by the total volume (0.021L+0.0066L=0.0276L) to obtain the concentration of the final salt:

[salt]=0.01428mol/0.0276L=0.517M

Now, we need to keep in mind that this is an acidic salt since the base is weak and the acid strong, so the determinant ionization is:

C_6H_5NH_3^++H_2O\rightleftharpoons  C_6H_5NH_2+H_3O^+

Whose equilibrium expression is:

Ka=\frac{[C_6H_5NH_2][H_3O^+]}{C_6H_5NH_3^+}

Now, since the Kb of C6H5NH2 is 4.3 x 10^-10, its Ka is 2.326x10^-5 (Kw/Kb), we can also write:

2.326x10^{-5}=\frac{x^2}{0.517M}

Whereas x is:

x=\sqrt{0.517*2.326x10^{-5}}\\\\x=3.47x10^-3

Which also equals the concentration of hydrogen ions; therefore, the pH at the equivalence point is:

pH=-log(3.47x10^{-3})\\\\pH=2.46

Regards!

6 0
2 years ago
It takes 495.0 kJ of energy to remove 1 mole of electron from an atom on the surface of sodium metal. How much energy does it ta
Zigmanuir [339]

Answer:

\lambda=241.9\ nm

Explanation:

The work function of the sodium= 495.0 kJ/mol

It means that  

1 mole of electrons can be removed by applying of 495.0 kJ of energy.

Also,  

1 mole = 6.023\times 10^{23}\ electrons

So,  

6.023\times 10^{23} electrons can be removed by applying of 495.0 kJ of energy.

1 electron can be removed by applying of \frac {495.0}{6.023\times 10^{23}}\ kJ of energy.

Energy required = 82.18\times 10^{-23}\ kJ

Also,  

1 kJ = 1000 J

So,  

Energy required = 82.18\times 10^{-20}\ J

Also, E=\frac {h\times c}{\lambda}

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

So,  

79.78\times 10^{-20}=\frac {6.626\times 10^{-34}\times 3\times 10^8}{\lambda}

\lambda=\frac{6.626\times 10^{-34}\times 3\times 10^8}{82.18\times 10^{-20}}

\lambda=\frac{10^{-26}\times \:19.878}{10^{-20}\times \:82.18}

\lambda=\frac{19.878}{10^6\times \:82.18}

\lambda=2.4188\times 10^{-7}\ m

Also,  

1 m = 10⁻⁹ nm

So,  

\lambda=241.9\ nm

6 0
3 years ago
Jason is preparing curry from an Indian cookbook his British brother-in-law gee him for his birthday. Unfortunately, the British
Marina CMI [18]

Answer:

0.99 pounds

2,000 oz

0.423 cups

Explanation:

In order  to convert this units we need to look up their equivalences.

1 g equals 0,0022 pounds approximately

Then we need to cross-multiply:

\frac{1 g}{0.0022 pounds} = \frac{450 g}{ Xpounds} \\x = \frac{450 g x 0.0022 pounds}{1 g}

450 g equals 0.99 pounds approximately

We can do the same calculation for the other 2 ingredients

1 g equals 16 oz

Then (125 g x 16 oz) / 1 oz = 2,000 oz  (or 500 4 oz)

1 cup equals 236.59 ml

Then (100 ml x 1 cup)/ 236.59 = 0.423 cups

6 0
3 years ago
"in which direction does this reaction tend to proceed under standard conditions?"
Black_prince [1.1K]

Answer : Right

Explanation : The direction of reaction tends to proceed on right side under standard conditions; If the change in standard free energy ΔG for a particular reaction is negative. Also if the elements in their most stable forms as they exist under standard conditions. Then ΔG determines the direction and extent of chemical change. But under standard conditions the direction of the  reaction will be to right.

6 0
3 years ago
Read 2 more answers
Which structure could a scientist look for in a plant that would identify it as a club moss rather than a liverwort?
Marianna [84]
<h3><u>Answer;</u></h3>

Phloem

<h3><u>Explanation;</u></h3>
  • <u>Club moss</u> plant belongs to the  the family Lycopodiaceae, Lycophyte includes any spore-bearing vascular plant.
  • <u>Liverworts</u> on the other hand are bryophytes which belongs to the division bryophyta. Bryophytes are small, non-vascular plants which includes mosses, hornworts and liverworts.
  • <em><u>Vascular plants contain vascular tissues which play an important role of transportation in plants. </u></em>The major vascular tissues are phloem and xylem. <em><u>Non-vascular plants</u></em> on the other hand lacks the vascular tissues for transportation of substances.
7 0
3 years ago
Read 2 more answers
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