If you could explain what “merkels” are, the question would be more clear.
The answer is 53.8 kJ.
Solution:There are two major steps in converting ice to liquid water. It begins with a phase change when ice melts at 0.0°C, and then a temperature change when the liquid water rises in temperature from zero to 32°C.
The amount of heat involved with the phase change melting is given by
q = (mass of water) (ΔHfus)
= (115.0 g)(334 J/g)
= 38410 J = 38.41 kJ
The amount of heat involved with temperature change is
q = mcΔT
= (115.0g)(4.184J/g°C)(32°C - 0.0°C)
= 15397.12 J = 15.39712 kJ
Summing up the two values gives the total heat required to convert ice to liquid water:
q = 38.41 kJ + 15.39712 kJ= 53.8 kJ
<span>for every 1 mole of Cu3(PO4)2, there are 2 moles of phosphorus. We also know that 1 mole of Cu3(PO4)2 has 6.022 x 10^23 atoms (Avogadro's number
</span>8.90 moles Cu3(PO4)22 moles P1 mol Cu3(PO4)21 mol Cu3(PO4)2<span>6.022 x 10^23 atoms
</span><span> (53.5958 x 10^23)/2 = 26.7979 x 10^23 atoms of P</span>
