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Bess [88]
3 years ago
14

One teaspoon equals 0.5 centiliters. How many liters equal 50 teaspoons? Round the answer to the nearest hundredth. 0.25 liters

0.50 liters 25 liters 50 liters
Mathematics
2 answers:
USPshnik [31]3 years ago
7 0
50 teaspoons = 0.246446 liters
0.246446 rounded to the nearest hundredth is 0.25

so your answer is 0.25
Goryan [66]3 years ago
3 0

Answer:

Your answer is 0.25

Step-by-step explanation:

Dont give me the brainiest give the other person the brainiest

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Write the equation in standard form for the circle with center (-5,8) and radius 4
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(x+5)^2+(y-8)^2=4^2

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2 years ago
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The factors of 35, 48, and 60 are listed below. Two of these numbers are relatively prime. Click the two numbers that are
Nostrana [21]

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35 and 48

Step-by-step explanation:

4 0
3 years ago
If the area of a rectangle is x^2+7x+12, what is the expression for the perimeter?
Cerrena [4.2K]

Length = 13 = (x + 3)

Width = 14 = (x + 4)

x2 + 7x + 12 = area of the rectangle

can be factored into

(x + 3)(x + 4)

Let L = one of the factors (x + 3)

Let W = the other factor (x + 4)

If x = 10 then

(10 + 3) = 13 = L

(10 + 4) = 14 = W

Checking this can be checked a couple of ways

Plug x = 10 into the original equation

x2 + 7x + 12

102 + 7(10) 12 = 100 + 70 + 12 = 182 = Area

Multiplty the factors

L x W = 13 x 14 = 182 = Area

I hope you find this useful if you have any questions please send me a message.

3 0
3 years ago
A tree that is next to a telephone pole is 15 feet tall and casts a shadow 4 feet long.
alekssr [168]

Answer:

24ft is the length of the shadow of the telephone pole

Step-by-step explanation:

Well first what I did was divide 15 by 4 which equaled to 3.75, after that the question said that the telephone pole was now 90 feet tall so I just had to divide 90 by 3.75 and then 24 ft long was the final answer. I hope that helps

4 0
2 years ago
Given the piecewise function shown below, select all of the statments that are true.
timurjin [86]
The <span>given the piecewise function is :
</span>
f(x) = \[ \begin{cases} &#10;      2x & x \ \textless \  1 \\&#10;      5 & x=1 \\&#10;      x^2 & x\ \textgreater \ 1 &#10;   \end{cases}&#10;\]

To find f(5) ⇒ substitute with x = 5 in the function → x²
∴ f(5) = 5² = 25


To find f(2) ⇒ substitute with x = 5 in the function → x²
∴ f(2) = 2² = 4

To find f(-2) ⇒ substitute with x = 5 in the function → 2x
∴ f(-2) = 2 * (-2) = -4

To find f(1) ⇒ substitute with x = 1 in the function → 5
∴ f(1) = 5
================================
So, the statements which are true:<span>
\framebox {B. f(2) = 4} \ \framebox {D. f(1) = 5}</span><span></span>
8 0
3 years ago
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