For this case we have to:
n: Represents the weight of Mary in Kg.
If your sister weighs 15 kg less we have:
Where "y" represents the weight of his sister in kg.
To find how many times Mary is heavier than her sister, we must divide Mary's weight by her sister's weight.
We have then:
Answer:
Mary is times heavier than her sister.
Answer:
x = 1
x = -5/8 + i* root( 39) / 8
or x = -5/8 - i* root( 39) / 8
Step-by-step explanation:
(x+x)^2 × -(x×(-1))=4+x-x^2
solve for x, show work.
(x+x)^2 × -(x×(-1)) = 4+x-x^2
Simplify:
(2x)^2 * (-(-x)) = 4 + x - x^2
4x*x * (-(-x)) = 4 + x - x*x
4*x*x*x = 4 + x - x*x
4*x*x*x - 4 = x *(1 - x)
4* (xxx - 1) = x * (1- x)
4* (x - 1)*( x*x +x + 1) = x (1 - x)
4( xx + x + 1) = -x
x = 1 is a solution.
4xx + 4x + 4 = -x
4xx + 5x + 4 = 0
x = -5/8 + root(25 - 4*4*4) / 2*4
x = -5/8 + i* root( 39) / 8
or x = -5/8 - i* root( 39) / 8
also x = 1
Answer:
Option 2?
Step-by-step explanation:
