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dsp73
3 years ago
11

Help please I need help

Mathematics
1 answer:
liberstina [14]3 years ago
5 0

Answer:

15/8

Step-by-step explanation:

Opp/Adj of angle x means Tan x

that would be 15/8

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I need help don't just give a random answer for the points pz got to get done quickly
saveliy_v [14]

Answer:

$140

Step-by-step explanation:

1 meal --- $15

8 meals --- $15 × 8 = $120

Total = $120 + $20

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3 years ago
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Alan has to finish an exam within 120 minutes. He finished the exam in 80 minutes. What is the percentage of the time he took fo
drek231 [11]

Answer:

66.67%

Step-by-step explanation:

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7 0
3 years ago
What are the vertical and horizontal asymptote of f(x)=2x/x-1
makvit [3.9K]
F(x)=2x/(x-1)

Denominator cannot be equal 0.
x-1=0
x=1  is vertical asymptote.

To find horizontal asymptote
we need divide the coefficients before x
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6 0
3 years ago
How to find the surface area of a prism??
Svetach [21]

Answer:

area of the two faces plus sides

6 0
2 years ago
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Crop researchers plant 15 plots with a new variety of corn. The yields in bushels per acre are: 138.0 139.1 113.0 132.5 140.7 10
son4ous [18]
There is a relationship between confidence interval and standard deviation:
\theta=\overline{x} \pm \frac{z\sigma}{\sqrt{n}}
Where \overline{x} is the mean, \sigma is standard deviation, and n is number of data points.
Every confidence interval has associated z value. This can be found online.
We need to find the standard deviation first: 
\sigma=\sqrt{\frac{\sum(x-\overline{x})^2}{n}
When we do all the calculations we find that:
\overline{x}=123.8\\ \sigma=11.84
Now we can find confidence intervals:
($90\%,z=1.645): \theta=123.8 \pm \frac{1.645\cdot 11.84}{\sqrt{15}}=123.8 \pm5.0\\($95\%,z=1.960): \theta=123.8 \pm \frac{1.960\cdot 11.84}{\sqrt{15}}=123.8 \pm 5.99\\ ($99\%,z=2.576): \theta=123.8 \pm \frac{2.576\cdot 11.84}{\sqrt{15}}=123.8 \pm 7.87\\
We can see that as confidence interval increases so does the error margin. Z values accociated with each confidence intreval also get bigger as confidence interval increases.
Here is the link to the spreadsheet with standard deviation calculation:
https://docs.google.com/spreadsheets/d/1pnsJIrM_lmQKAGRJvduiHzjg9mYvLgpsCqCoGYvR5Us/edit?usp=sharing
6 0
3 years ago
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