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3 years ago

If anybody willing to help me with my geometry work that’s done by 6pm please contact me by my number 9014132287

Mathematics

1 answer:

My name is Ann [436]3 years ago

4 0

Do not listen to those bots

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5 (2+5) 2 2 715cm? value of h

kirill115 [55]

Answer:

Is this a complete question?

7 0

3 years ago

Solve the equation. Can you please answer as soon as you can? Thanks!

nikitadnepr [17]

Answer:

Step-by-step explanation:

It’s zero

4 0

3 years ago

Abby needs to take a taxi to go to the movies, the taxi charges 4.00 flag fee for the pick up and then 2.75 for each mile driven

AlexFokin [52]

Answer:

6 miles

Step-by-step explanation:

x = miles driven

4.00 + 2.75 * x = 20.50

2.75x = 20.50 - 4.00 = 16.50

x = 16.50/2.75 = 6 miles

5 0

2 years ago

You are planning a survey of starting salaries for recent computer science majors. In a recent survey by the National Associatio

nydimaria [60]

Answer:

A sample size of 554 is needed.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Standard deviation is known to be $12,000

This means that $\sigma = 12000$

What sample size do you need to have a margin of error equal to $1000, with 95% confidence?

This is n for which M = 1000. So

$M = z\frac{\sigma}{\sqrt{n}}$

$1000 = 1.96\frac{12000}{\sqrt{n}}$

$1000\sqrt{n} = 1.96*12$

Dividing both sides by 1000:

$\sqrt{n} = 1.96*12$

$(\sqrt{n})^2 = (1.96*12)^2$

$n = 553.2$

Rounding up:

A sample size of 554 is needed.

5 0

2 years ago

Enter the equation in standard form. y=9/3x-5/3

Marianna [84]

y = 9/3 x - 5/3
3y = 9x - 5
9x - 3y = 5 ...<----this is standard form

3 0

3 years ago