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3 years ago

What is 18123÷20 can you please write it our

Mathematics

2 answers:

Mandarinka [93]3 years ago

8 0

The answer is 18123/20= 906.15

-BARSIC- [3]3 years ago

7 0

906.15 that’s your answer

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3x - 4y when x = 3 and y=2 Help pls and thank you

Maurinko [17]

Answer:

substitute the unknown with the values given ie

3(3) - 4 (2)

you get 9-8

= 1

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3 years ago

Solve for w. 5w + 9z = 2z + 3w

Margaret [11]

Answer:

w = -7z/2

Step-by-step explanation:

Our goal is to isolate w

1. subtract 3w from both sides to get 2w+9z = 2z

2. Subtract 9z from both sides to get 2w = -7z

3. Divide both sides by 2 to get w = -7z/2

We cannot simplify further, so this is our answer.

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3 years ago

Janice has a box of colored pencils. She shares them equally with her friend Tracy. Her sister Nicole gives her two more colored

zhuklara [117]

Answer:

Step-by-step explanation:

do the math

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3 years ago

Round to the nearest hundredth (2 decimal places) when necessary

den301095 [7]

Answer:

18.22 is the circumference

hope this helps

have a good day :)

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Mai wants to make an open top box by cutting out corners of a square piece of cardboard and folding up the sides. The cardboard

Bumek [7]

Answer:

$V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

The domain for x is all real numbers greater than zero and less than 5 com

Step-by-step explanation:

The question is

What is the volume of the open top box as a function of the side length x in cm of the square cutouts?

see the attached figure to better understand the problem

Let

x -----> the side length in cm of the square cutouts

we know that

The volume of the open top box is

$V=LWH$

we have

$L=(10-2x)\ cm$

$W=(10-2x)\ cm$

$H=x)\ cm$

substitute

$V(x)=(10-2x)(10-2x)x\\\\V(x)=(100-40x+4x^{2})x\\\\V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

Find the domain for x

we know that

$(10-2x) > 0\\10> 2x\\ 5 > x\\x < 5\ cm$

The domain is the interval (0,5)

The domain is all real numbers greater than zero and less than 5 cm

therefore

The volume of the open top box as a function of the side length x in cm of the square cutouts is

$V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

5 0

3 years ago