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2 years ago

Use the relationship between the angles in the figure to answer the question.

Mathematics

2 answers:

Brut [27]2 years ago

6 0

Answer:

x + 49 + 28 = 180

Step-by-step explanation:

The angles on a straight line with x° are 28° and 49° respectively, side by side with x°. This is because, vertical angles are equal. Therefore, the angle vertically opposite 28° and 49° are equal to 28° and 49° respectively.

Therefore, since angles on a straight line is 180°, thus:

x + 49 + 28 = 180

satela [25.4K]2 years ago

5 0

Answer:

x + 49 + 28 = 180

Step-by-step explanation:

THIS ANSWER IS CORRECT

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If d = the number of dogs, which variable expression represents the phrase below? the sum of the number of dogs and the 6 cats.

s344n2d4d5 [400]

Answer:

Step-by-step explanation:

" Sum" means "+".

The sum of the number of dogs and the 6 cats.

d + 6

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3 years ago

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If the flour to sugar ratio is 4 cups flour to 1 cup sugar, then how much sugar do you need if you only use 2 cups of flour?

miss Akunina [59]

you would need half a cup of sugar

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2 years ago

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When Mohammed was born, the baby was 21 inches tall. at his last check up, he was 38 inches tall. what is the percent increase i

denis23 [38]

Answer:

80.95

Step-by-step explanation:

Percentage increase = $\frac{New Value - Old Value}{Old Value}$ *100

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2 years ago

In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa

Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

$^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434$

Hence, the required number of ways =27434

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2 years ago

What's the answer for 2 and 3

Andrews [41]

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3 years ago