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Ede4ka [16]
2 years ago
12

I found the answer, it's 6. so just put 6 and you can have the points

Mathematics
1 answer:
egoroff_w [7]2 years ago
6 0
4 because if u where to fold it
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1. What is the area of a circle with a diameter of 3.4 cm? Round your answer to the nearest tenth. (use 3.14 for pi)
Brilliant_brown [7]
1. The area of a circle is
a = \pi {r}^{2}
\pi = 3.14 \\ r =  \frac{3.4}{2}  = 1.7
a = (3.14) {(1.7)}^{2}  \\  = 9.0746
The area is 9.07 cm^2.

2. The volume of a cube is
v =  {s}^{3}
s = 4.5
v =  {(4.5)}^{3}  \\  = 91.125
The volume is 91.125 m^3
7 0
3 years ago
How many pennies could you have if: When you Break de Pennies into groups of 2, you have 1 penny left over, AND when you break t
MariettaO [177]

Answer:

The answer is 31 pennies

Step-by-step explanation:

we have to find a number that gives a remainder of 1 when divided by both 2, 3 and 5.

The easiest way to do this is to list the factors of 5, add 1 to it, and test them until we find the one with a remainder of 1 by all three divisors. This is done as follows:

1) factor: 5 (+1) = 6

6 ÷ 2 = 3 remainder 0

6 ÷ 3 = 2 remainder 0

since there is a remainder of 0, when divided by 3, 6 is wrong

2) factor; 10 (+1) = 11

11 ÷ 3 = 3 remainder 2 ( 11 is not the correct answer

3) factor : 15 (+1) = 16

16 ÷ 2 = 8 remainder 0 ( 16 is  not the correct answer

4) factor : 20(+1) = 21

21 ÷ 3 = 7 remainder 0 ( 21 is wrong)

5) factor : 25(+1) = 26

26 ÷ 2 = 13 remainder 0 ( 26 is wrong)

6) factor : 30(+1) = 31

31 ÷ 2 = 15 Remainder 1

31 ÷ 3 = 10 Remainder 1

31 ÷ 5 = 6 Remainder 1

since all three divisors give a remainder of 1, the correct answer is 31

Therefore you have 31 pwnnies

6 0
3 years ago
Vince added 0.912,0.882 ,and 1.354 liters of liquid to a bottle.About how much is in the bottle?
Levart [38]
3.148 liters of liquid. 
3 0
3 years ago
I need help please.!
gulaghasi [49]
Hey ! I know for sure A is one of the correct answers i’m working on the rest now
8 0
3 years ago
Solve for x
alexira [117]

Check the picture below.

7 0
3 years ago
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