Answer:
equation of the circle J with center K(-7,3) and radius 6 is=
x^2+y^2+14x-6y+22=0
Step by step explanation:
Equation of circle with given centre (h,k) and radius r is
(x-h)^2+(y-k)^2=r^2
Given centre are K(-7,3) and radius 6.
So equation of Circle=
(x- -7)^2+(y-3)^2=6^2
x^2+14x+49+y^2-6y+9=36
x^2+y^2+14x-6y+22=0 answer
2x+3x+x+9 = ??
5x+x+9 = ??
6x+9= ??
6x = -9 ---- subtract 9 on both sides
x = - 3/2 ----- didvide by 6 on both sides, simplify
That's 33/100 and can't be simplified. If you had said that the 3s keep going and never end, then it would have been 1/3. But as written, it's just 33/100.
Answer:
Options 2 and 4.
Step-by-step explanation:
Line MK is the perpendicular bisector of line LN, because it cuts through its midpoint.
Line ML is equal to line MN because it is a kite, and a kite has two adjacent sides equal.
all real numbers such that y is less than or equal to 4
