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Jobisdone [24]
3 years ago
14

Answer my question about this one please

Mathematics
1 answer:
Leokris [45]3 years ago
6 0
The answer is 11 I hope this helped you
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On a map, the distance between two towns is 12 centimeters. If 3 centimeters represents 90 miles, what is the actual distance be
dolphi86 [110]
360 miles, I’m pretty sure
6 0
2 years ago
BRAINLIEST IF CORRECT
lbvjy [14]

Answer:

Step-by-step explanation:

the first is 1/2

second is 1/52

third is 1/4

forth is 1/8

i think thats right any way :)

7 0
3 years ago
Read 2 more answers
 Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III
vodka [1.7K]

Given:

\sin x=-\dfrac{15}{17}

x lies in the III quadrant.

To find:

The values of \sin 2x, \cos 2x, \tan 2x.

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others  are negative.

We know that,

\sin^2 x+\cos^2 x=1

(-\dfrac{15}{17})^2+\cos^2 x=1

\cos^2 x=1-\dfrac{225}{289}

\cos x=\pm\sqrt{\dfrac{289-225}{289}}

x lies in the III quadrant. So,

\cos x=-\sqrt{\dfrac{64}{289}}

\cos x=-\dfrac{8}{17}

Now,

\sin 2x=2\sin x\cos x

\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})

\sin 2x=-\dfrac{240}{289}

And,

\cos 2x=1-2\sin^2x

\cos 2x=1-2(-\dfrac{15}{17})^2

\cos 2x=1-2(\dfrac{225}{289})

\cos 2x=\dfrac{289-450}{289}

\cos 2x=-\dfrac{161}{289}

We know that,

\tan 2x=\dfrac{\sin 2x}{\cos 2x}

\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}

\tan 2x=\dfrac{240}{161}

Therefore, the required values are \sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}.

7 0
2 years ago
2x + 8y = 6<br> 5x + 20y = 15<br><br> I there a solution , no solution , or many solution ?
WARRIOR [948]

Answer:

1 solution

Step-by-step explanation:

Solution is, x=3-4y

4 0
2 years ago
Plz help me. first to answer get brainliest
laiz [17]

Answer:

A 28 because 7 times four

Step-by-step explanation:

4 0
3 years ago
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