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Scorpion4ik [409]
3 years ago
11

Write the recursive, arithmetic and explicit formula for the nth term of the sequence:

Mathematics
1 answer:
Ivanshal [37]3 years ago
5 0

Recursive Formula

\begin{cases}a_1 = 8\\a_n = a_{n-1}-7\end{cases}

The top row says the first term is 8

The bottom row says that to get the nth term, we subtract 7 from the (n-1)th term. So basically we subtract 7 from each term to get the next term.

Note the subscripts tell us which term we're working with.

======================================================

Arithmetic Formula

We have a = 8 as the first term and d = -7 as the common difference.

a(n) = a + d(n-1)

a(n) = 8 + (-7)(n-1)

a(n) = 8 - 7n + 7

a(n) = -7n+15

The nth term arithmetic formula is a(n) = -7n+15

If you plug in n = 1, you should get a(n) = 8

If you plug in n = 2, you should get a(n) = 1

and so on.

=======================================================

Finding the 10th term

Plug in n = 10 to get

a(n) = -7n+15

a(10) = -7(10)+15

a(10) = -70+15

a(10) = -55

The 10th term is -55

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Hey there!

108 divided by 7(days in a week)= about 15.43 pounds of meat each day

Hope this helps!
7 0
4 years ago
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What is the inverse operation of multiply by 12? A. add 12 B. subtract 12 C. multiply by 12 D. divide by 12​
Liula [17]

Answer:

D. divide by 12​

Step-by-step explanation:

→ When you :

- Multiply, the inverse is divide

- Divide, the inverse is multiply

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- Minus, the inverse is add

6 0
3 years ago
Factor each.<br><br><br> Please help!
Naddika [18.5K]

Answer:

1) The factors of  x^2-3x+2=0 are \mathbf{(x-1)(x-2)=0}

Option C is correct.

3) The factors of  x^2+2x-8=0 are \mathbf{(x-2)(x+4)=0}

Option B is correct.

Step-by-step explanation:

1) Factor : x^2-3x+2=0

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : -3x

We can break them as (-2x)( -x)

Solving:

x^2-3x+2=0\\x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0

So, factors of  x^2-3x+2=0 are \mathbf{(x-1)(x-2)=0}

Option C is correct.

3) Factor: x^2+2x-8=0

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : 2x

We can break them as (4x)( -2x)

Solving

x^2+2x-8=0\\x^2+4x-2x-8=0\\x(x+4)-2(x+4)=0\\(x-2)(x+4)=0

So, factors of  x^2+2x-8=0 are \mathbf{(x-2)(x+4)=0}

Option B is correct.

7 0
3 years ago
Simplify the expression8(5 plus w)
inna [77]

8(5 plus w)

distribute

8*5 + 8*w

40 + 8w


8 0
3 years ago
HELP!!!! <br> Solve x=9w−3z−15 for w. Do not write w= in your answer.
Tresset [83]

Answer:

Your answer is: x/9 + z/3 + 5/3

Isolate the variable by dividing each side by factors that don't contain the variable.

Step-by-step explanation:

Hope this helped : )

5 0
3 years ago
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