Does anybody know how to do #1, very confused?

The angular velocity of a fan blade is 6.2 radians per second.

MA_775_DIABLO [31]

Answer:

94.7 revolutions

Step-by-step explanation:

In the question above, we are given the following values for the fan

Angular velocity = 6.2 radians per seconds

Time = 1.6 minutes.

Step 1

We would convert the time given to seconds

1 minute = 60 seconds

1.6 minutes = ?

We cross multiply

1.6 minutes × 60 seconds

= 96 seconds

Step 2

Number of revolutions made by the fan is calculated as :

Angular velocity(rad/s)

× time(seconds)

Number of revolutions = 6.2 radians per seconds × 96 seconds

=595.2 radians

Converting from radians to revolution

1 radian = 0.159155 revolutions

595.2 radians =

Cross multiply

= 595.2 radians × 0.159155 revolutions

= 94.729056 revolutions.

Approximately to the nearest tenth = 94.7 revolutions.

Therefore, the number of revolutions the fan blade makes in 1.6 minutes is 94.7 revolutions.

8 0

3 years ago

6 helppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp

jeka94

A) 15
B) 4
C) 225
D) 450

8 0

3 years ago

Read 2 more answers

Help with math please???

Tresset [83]

Okay, let's see...

The problem is asking for a linear equation most likely in the form of y=mx+b

y is another way to say f(x)

m = slope

b = y intercept

Let's start with the y intercept first.

Y intercept means ' When does the line touch (intercept) the y axis.

In this case, if you look at the graph, the line touches the y axis at -1.

-1 will replaces b

To find the slope we are going to take 2 precise points from the graph.

Lets use (0,-1) and (-6,4)

To find the slope, we're going to use $\frac{(y_{2} -y_{1} )}{(x_{2} -x_{1} )}$

4 - (-1) / -6 - 0

Solve, our slope is 5/-6

That is our m

Our final equation is

$f(x)=\frac{-5}{6} x -1$

3 0

3 years ago

Passes through (3,-6) and (-1,2) slope intercept form?

IRISSAK [1]

Answer:

2/1

Step-by-step explanation:

8/4 which is also 2/1

7 0

3 years ago

4 Tan A/1-Tan^4=Tan2A + Sin2A

Eva8 [605]

tan(2A) + sin(2A) = sin(2A)/cos(2A) + sin(2A)

• rewrite tan = sin/cos

… = 1/cos(2A) (sin(2A) + sin(2A) cos(2A))

• expand the functions of 2A using the double angle identities

… = 2/(2 cos²(A) - 1) (sin(A) cos(A) + sin(A) cos(A) (cos²(A) - sin²(A)))

• factor out sin(A) cos(A)

… = 2 sin(A) cos(A)/(2 cos²(A) - 1) (1 + cos²(A) - sin²(A))

• simplify the last factor using the Pythagorean identity, 1 - sin²(A) = cos²(A)

… = 2 sin(A) cos(A)/(2 cos²(A) - 1) (2 cos²(A))

• rearrange terms in the product

… = 2 sin(A) cos(A) (2 cos²(A))/(2 cos²(A) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(A)

… = 4 sin(A) cos(A) / (2 - 1/cos²(A))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(A) cos(A) / (2 - sec²(A))

• divide through again by cos²(A)

… = (4 sin(A)/cos(A)) / (2/cos²(A) - sec²(A)/cos²(A))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(A) / (2 sec²(A) - sec⁴(A))

• factor out sec²(A) in the denominator

… = 4 tan(A) / (sec²(A) (2 - sec²(A)))

• rewrite using the Pythagorean identity, sec²(A) = 1 + tan²(A)

… = 4 tan(A) / ((1 + tan²(A)) (2 - (1 + tan²(A))))

• simplify

… = 4 tan(A) / ((1 + tan²(A)) (1 - tan²(A)))

• condense the denominator as the difference of squares

… = 4 tan(A) / (1 - tan⁴(A))

(Note that some of these steps are optional or can be done simultaneously)

7 0

3 years ago