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Sergeeva-Olga [200]
3 years ago
8

PLEASE HELP IT"S URGENT Which figure has the greater Volume??

Mathematics
1 answer:
Aneli [31]3 years ago
6 0
I cannot see the picture ?
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Can anybody help me with this?
vlada-n [284]
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p^5/5 is the same as p^1 or just p.

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2 years ago
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Start with -2 and you end with +7 what is the rule
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Add 9 because -2 to 7 equals 9 hope this helped


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3 years ago
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Solve the system of equations<br> y=x^2-3x+4<br> x+y=4<br> show all work please!
Debora [2.8K]

Answer:

(0,4)

(2,2)

Step-by-step explanation:

y=x^2-3x+4

x+y=4

the second one can be rewritten as y=4-x

so the system becomes

y=x^2-3x+4

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we can write it as x(x-2)=0 a product is = 0 when one of its factors = 0

so the solutions for x are: x=0 and x-2= 0 that means x=2

to get y you simply use 0 and 2 as value of x for any of the two equations

and you get y=4 and y=2 respectively

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The answer is 7x(x+1)=0
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Find the exact value of sin2 theta given sin theta =5/13, 90°&lt;theta &lt;180°
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Now, we know that 90°< θ <180°, that simply means the angle θ is in the II quadrant, where sine is positive and cosine is negative.

\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{13}}\impliedby \textit{now let's find the \underline{adjacent side}}&#10;\\\\\\&#10;\textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}

\bf \pm\sqrt{13^2-5^2}=a\implies \pm\sqrt{144}=a\implies \pm 12 =a \implies \stackrel{II~quadrant}{-12=a}&#10;\\\\\\&#10;therefore \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{-12}}{\stackrel{hypotenuse}{13}}&#10;\\\\&#10;-------------------------------\\\\&#10;sin(2\theta )\implies 2sin(\theta )cos(\theta )\implies 2\left(\frac{5}{13}  \right)\left( \frac{-12}{13} \right)\implies -\cfrac{120}{169}
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3 years ago
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