Answer:
0.1 N
Explanation:
Considering the relationship between force,
spring constant and extension as defined by Hook's law
The force F=xk as from Hooke's law where F is the force of the spring, k is spring constant and x is extension or compression. Substituting 2 N/m for k and 5cm which is equivalent to 0.05 m for extention x then the force will be
F=2*0.05=0.1 N
Answer:
C
Explanation:
please mark as brainliest
Answer:
W 1920 N
Explanation:
200kg at a location where g=9.6m/s^2
Answer:
The work done by Joe, W_joe, when he raises the barbell to finish one repetition is 211.98J
The correct option is Wsam <W_Joe.
Explanation:
From the mass of the bar, the acceleration of gravity and the distance that the bar travels in each of them when performing the lifting movement from the chest you can calculate the work done by each one:
W_joe= 31.5kg × 9.81 (m/s^{2} ) × 0.686m = 211.98J
W_sam= 31.5kg × 9.81 (m/s^{2} ) × 0.608m = 187.88J
187.88J < 211.98J ⇒ Wsam <W_Joe
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