Explanation:
acc is velocity over time and the velocity rule is distance over time ..so acc would be distance over time power2
From the basic "heat lost by hot object=heat gained by colder object" principle, we have
m1c1ΔT1=m2c2ΔT2
where m1= 1kg
m2=4kg
c1=900J/kg k
c2=4200J/kg k
With this information at hand we have
m1c1(90-T)=m2c2(T-25)
after substituting the given values we can find that
T=28.3^{0}c
What is your question can you show pictures?
The final velocity of the cart at the given mass is 4.36 m/s.
The given parameters;
- <em>mass of the cart, m = 1 kg</em>
- <em>work done on the cart, W = 5 J</em>
- <em>initial velocity of the cart, u = 3 m/s</em>
The distance traveled by the cart is calculated as follows;
Fd = W
mgh = W
The final velocity of the cart is calculated as follows;
Thus, the final velocity of the cart at the given mass is 4.36 m/s.
Learn more here:brainly.com/question/17956487