To develop this problem, it is necessary to apply the concepts related to Faraday's law and Magnetic Flow, which is defined as the change that the magnetic field has in a given area. In other words
Where
B= Magnetic Field
A = Area
Angle between magnetic field lines and normal to the area
The differentiation of this value allows us to obtain in turn the induced emf or electromotive force.
In this case we have that the flat loop of wire is perpendicular to the magnetic field, therefore the angle is 0 degrees, since its magnetic field acts parallel to the area:
0 then our expression can be written as
From the same value of the electromotive force we have to
Replacing we have
Replacing with our values we have that
Therefore the magnitude of the induced emf in the loop is 0.0237V
On the other hand we have that the current by Ohm's Law can be defined as
For the given value of the resistance and the previously found potential we have to
Answer:
Option D: 4 mm⁴
Explanation:
Formula for area moment of inertia for a circular cross-section is;
I = πd⁴/64
We are given diameter;
d = 3 mm
Thus;
I = π × 3⁴/64
I = 3.98 mm⁴
Approximating to a whole number gives;
I = 4 mm⁴
Explanation :
Noble gases are the elements of group 18. This series contains helium, neon, radon krypton and radon.
The noble gases are the least reactive of any elements on the periodic table. This is because they have eight valance electrons in its outermost shell.
Non-metals or poly atomic ions forms acidic compounds with hydrogen. For example : etc forms acidic compounds with hydrogen.
The halogens are the most reactive among all the elements. This is because halogens suddenly combines with most of the metals. They are never seen uncombined in nature.
For example : Chlorine, fluorine and astatine are some halogens.