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Maksim231197 [3]
3 years ago
9

Anyone knows how to do this? I think it’s 0 because it’s not moving————

Physics
1 answer:
dedylja [7]3 years ago
8 0

Answer:

1 m/s  

Explanation:

2 to 3 second interval would be zero.

3 to 4 is 2 m/s

so average is 1 m/s

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A toy rocket launcher can project a toy rocket at a speed as high as 35.0 m/s.
Anestetic [448]

Answer:

(a) 62.5 m

(b) 7.14 s

Explanation:

initial speed, u = 35 m/s

g = 9.8 m/s^2

(a) Let the rocket raises upto height h and at maximum height the speed is zero.

Use third equation of motion

v^{2}=u^{2}+2as

0^{2}=35^{2}- 2 \times 9.8 \times h

h = 62.5 m

Thus, the rocket goes upto a height of 62.5 m.

(b) Let the rocket takes time t to reach to maximum height.

By use of first equation of motion

v = u + at

0 = 35 - 9.8 t

t = 3.57 s

The total time spent by the rocket in air = 2 t = 2 x 3.57 = 7.14 second.

8 0
3 years ago
How much time would it take for the sound of thunder to travel 2000 meters if sound travels of 330 meters per sec
Lubov Fominskaja [6]
2000÷330=6.06 repatant so the answer would be about 6.06 seconds
4 0
3 years ago
Read 2 more answers
Our eyes can see light with an angular resolution of about 1’—equivalent to about a third of a millimeter at arm’s length. Suppo
olya-2409 [2.1K]

Answer:

We would not be able to make our way around the earth's surface, to read, to sculpt or to create technology because we cannot see!

Explanation:

The minimum angular separation that can be distinguished by an eye gives the angular resolution of the eye.

Given that the Angular resolution with infrared radiation is = 1.0^0 equal to 60'

This resolution is very much greater than that of the eye (1')

The angular resolution that our eyes can see is about  \frac{1}{3}mm  at arms length

Angular resolution of infrared = \frac{1}{3} * 60 = 20mm  at arms length

We therefore cannot read, sculpt or create technology because we cannot see.

7 0
3 years ago
Jill leaves home and rides a distance of 70 km. It took her 2.5 hours. What is her speed?
Paraphin [41]
The answer is ...
28 km per hour
5 0
3 years ago
Two steel guitar strings have the same length. String A has a diameter of 0.513 mm and is under 403 N of tension. String B has a
Mnenie [13.5K]

Answer:

\frac{v_{A}}{v_{B}} = 1.785

Explanation:

T_{A} = Tension force in string A = 403 N

T_{B} = Tension force in string B = 800 N

d_{A} = diameter of string A = 0.513 mm

d_{B} = diameter of string B = 1.29 mm

v_{A} = wave speed of string A

v_{B} = wave speed of string B

Ratio of the wave speeds is given as

\frac{v_{A}}{v_{B}} = \sqrt{\frac{T_{A}}{T_{B}}} \left ( \frac{d_{B}}{d_{A}} \right )

\frac{v_{A}}{v_{B}} = \sqrt{\frac{403}{800}} \left ( \frac{1.29}{0.513} \right )

\frac{v_{A}}{v_{B}} = 1.785

5 0
3 years ago
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