3 years ago

Help me pretty please

Mathematics

1 answer:

Solnce55 [7]3 years ago

8 0

Answer:

I believe its 3.4-?

Step-by-step explanation:

You might be interested in

Verify that triangle ABC is equal to DEF . Find the scale factor of triangle ABC to triangle DEF

alexira [117]

Answer:

k = 6 : 5 : 4

Step-by-step explanation:

BC : AB : AC = 18 : 15 : 12 = 6 : 5 : 4

EF : DE : DF = 12 : 10 : 8 = 6 : 5 : 4

5 0

3 years ago

Olivia's class collected 3,591 bottle caps in 57 days. The same number of bottle caps were collected each day. How many bottle c

irinina [24]

This is a great question for a calculator

But anyway all you have to do is divide 3,591 by 57 to find your answer which the answer is 63 bottle caps per day

3 0

3 years ago

Read 2 more answers

a salesperson earns 1/20 commission the sale of each car they sell. What is the commission earned on a car sold for $9,800? show

Law Incorporation [45]

Answer:

$490

Step-by-step explanation:

$9800 * 1/20 = $490

9800 * 5% = $490

7 0

3 years ago

Write by what rule you know the triangles are congruent, or write CNBD for "Cannot be determined." Segments and angles are congr

Triss [41]

RSM huh. I feel bad. I'm in this too.

4 0

3 years ago

Assume that a procedure yields a binomial distribution with a trial repeated n = 5 times. Use some form of technology to find th

Digiron [165]

Answer:

$P(X = 0) = 0.0263$

$P(X = 1) = 0.1407$

$P(X = 2) = 0.3012$

$P(X = 3) = 0.3224$

$P(X = 4) = 0.1725$

$P(X = 5) = 0.0369$

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 5, p = 0.517$

Distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.517)^{0}.(0.483)^{5} = 0.0263$

$P(X = 1) = C_{5,1}.(0.517)^{1}.(0.483)^{4} = 0.1407$

$P(X = 2) = C_{5,2}.(0.517)^{2}.(0.483)^{3} = 0.3012$

$P(X = 3) = C_{5,3}.(0.517)^{3}.(0.483)^{2} = 0.3224$

$P(X = 4) = C_{5,4}.(0.517)^{4}.(0.483)^{1} = 0.1725$

$P(X = 5) = C_{5,5}.(0.517)^{5}.(0.483)^{0} = 0.0369$

6 0

3 years ago

Help me pretty please ​

Help me pretty please