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3 years ago

The simplified answer of 6/35

Mathematics

2 answers:

Rzqust [24]3 years ago

7 0

The simplified answer of 6/35 is 6/35. It is in simplest form.

lukranit [14]3 years ago

7 0

6/35 can not be simplified it would just equal the same answer

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A dilation with a scale factor of 2 is applied to the three line segments shown. The resulting images are P′Q′¯¯¯¯¯¯¯, A′B′¯¯¯¯¯

ivanzaharov [21]

Answer:

Step-by-step explanation:

Formula to determine the scale factor,

Scale factor = $\frac{\text{Dimension of the image}}{\text{Dimension of the original}}$

2 = $\frac{P'Q'}{PQ}$

2 = $\frac{P'Q'}{2}$

P'Q' = 4 cm

Similarly, for the length of A'B',

2 = $\frac{A'B'}{AB}$

2 = $\frac{A'B'}{1.5}$

A'B' = 3 cm

For the length of M'N',

2 = $\frac{M'N'}{MN}$

2 = $\frac{M'N'}{3}$

M'N' = 6 cm

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3 years ago

You pick a marble from a bag containing three black, four striped, and three white. What is the probability you will choose eith

bezimeni [28]

Answer:

Step-by-step explanation:

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The graph of the function f is shown. f(0) =<br> A) f(-1) <br> B) f(2) <br> C) f(3) <br> D) f(4)

aalyn [17]

f(0) means x = 0

so when x = 0, y = -5

and when x = 4, f(4) is also equal -5 (y = -5)

so f(0) = f(4) = -5

Answer

D) f(4)

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3 years ago

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Which are vertical angles?

zhuklara [117]

Answer:

The verticle angles are AB and ED

Step-by-step explanation:

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Two cargo ships spot a signal fire on a small island. The captains know they are 140 feet

Irina18 [472]

The distance from Ship B to the signal fire at point C is $405.4 \mathrm{ft}$

Explanation:

It is given that two ships A and B are at a distance 140 ft from each other.

The angle formed by ship A is 82º and the angle formed by ship B is 78º.

To determine the distance from ship B to the signal fire at point C, we need to know the another angle.

Hence, we have,

$\begin{aligned}\angle A+\angle B+\angle C &=180^{\circ} \\82^{\circ}+78^{\circ}+\angle C &=180^{\circ} \\160^{\circ}+\angle C &=180^{\circ} \\\angle C &=20^{\circ}\end{aligned}$

Now, we shall solve the problem using the law of sines,

$\frac{\sin A}{a}=\frac{\sin C}{c}$

Substituting the values, we have,

$\frac{\sin 82^{\circ}}{a}=\frac{\sin 20^{\circ}}{140}$

$\frac{0.9903}{a}=\frac{0.3420}{140}$

Simplifying, we get,

$a=\frac{0.9903 \times 140}{0.3420}$

$a=405.4$

Thus, the distance from Ship B to the signal fire at point C is $405.4 \mathrm{ft}$

4 0

3 years ago