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Sholpan [36]
3 years ago
5

A math teacher wants to find out the average number of hours his students spend working on their math homework for his class eac

h week. Which group best represents a sample of the population?
Mathematics
2 answers:
HACTEHA [7]3 years ago
5 0

Answer:

the answer is C. 30 students selected from his class roster.

Step-by-step explanation:

Nataly [62]3 years ago
4 0
What are the options...
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1st to answer will get Brainliest 
storchak [24]
Find current interest:
=$2543.32 * 17.4%
=2543.32 * 0.174
=442.537

Add the interest to the current balance:
=2543.32 + 442.537
=2985.857

Add new transaction:
=2985.857 + 320
=3305.857 rounded to 3305.86

The answer is C) $3305.86

Hope this helps! :)
4 0
3 years ago
Read 2 more answers
2. How do you<br> multiply and divide<br> rational<br> expressions?
tatuchka [14]

Answer:

1.Factor both the numerator and the denominator.

2.Write as one fraction.

3: Simplify the rational expression.

4: Multiply any remaining factors in the numerator and/or denominator.

Step-by-step explanation:

7 0
3 years ago
Can you please help me out on this one ​
vampirchik [111]

Answer:

9

Step-by-step explanation:

You need to divide 54 by 6

4 0
3 years ago
Read 2 more answers
Help help help help help help help help help help
Mumz [18]

Answer:

times the numbers

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the following: F(x, y, z) = e^(xy) sin z j + y tan^−1(x/z)k Exercise Find the curl and the divergence of the vector field.
natulia [17]

\vec F(x,y,z)=e^{xy}\sin z\,\vec\jmath+y\tan^{-1}\dfrac xz\,\vec k

Divergence is easier to compute:

\mathrm{div}\vec F=\dfrac{\partial(e^{xy}\sin z)}{\partial y}+\dfrac{\partial\left(y\tan^{-1}\frac xz\right)}{\partial z}

\mathrm{div}\vec F=xe^{xy}\sin z-\dfrac{xy}{x^2+z^2}

Curl is a bit more tedious. Denote by D_t the differential operator, namely the derivative with respect to the variable t. Then

\mathrm{curl}\vec F=\begin{vmatrix}\vec\imath&\vec\jmath&\vec k\\D_x&D_y&D_z\\0&e^{xy}\sin z&y\tan^{-1}\frac xz\end{vmatrix}

\mathrm{curl}\vec F=\left(D_y\left[y\tan^{-1}\dfrac xz\right]-D_z\left[e^{xy}\sin z\right]\right)\,\vec\imath-D_x\left[y\tan^{-1}\dfrac xz\right]\,\vec\jmath+D_x\left[e^{xy}\sin z}\right]\,\vec k

\mathrm{curl}\vec F=\left(\tan^{-1}\dfrac xz-e^{xy}\cos z\right)\,\vec\imath-\dfrac{yz}{x^2+z^2}\,\vec\jmath+ye^{xy}\sin z\,\vec k

5 0
3 years ago
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