The area of square: s · s = s²
The area of rectangle: (s + 6) · s = s(s + 6)
So:
s² + s(s + 6) = 56
s² + s(s + 6) - 56 = 0
Answer D.
Answer:
-6
Step-by-step explanation:
imagine you're on a line graph you start at zero and then go backward 15 spaces and move forward 9 spaces where does that leave you
301
We could start by finding the lowest common multiple of 2, 3, 4, 5, and 6, which is 60. Then, we can consider the next few multiples: 120, 180, 240, 300...
However, because we need a remainder of 1 when our number is divided by each of these numbers (2,3,4,5,6), we want to go one above each of these multiples. So we're talking about 61, 121, 181, 241, 301... Those are the numbers that will satisfy the "remainder of 1" part of the question.
Now, we need to find out which one satisfies the other part of the question, which just requires dividing each of these numbers by 7 to see which is divisible by 7 (in other words, which one gives us a remainder of zero when we divide by 7).
301 does it. 301/7 = 43. So 301 is a multiple of 7 and therefore will yield no remainder when divided by 7.
Hope this all makes sense.
Answer:
you muliply first 9×7 and then carry the remainder to the other side and then 9×2 and add the remainder
<span>If it decreases by 12 percent, you do 19,200x.12 which is 2,304. You subtract that from 19,200 which is 16,896. You multiply that by .12 which is 2,027.52 and subtract that from 16,896 which is 14,868.42. You do that three more times and there's your answer.
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