2 years ago

Determine whether the relation is a function: (3, 2), (1, 2), (4, 3), (6, -2)

Mathematics

1 answer:

GenaCL600 [577]2 years ago

5 0

Answer:

it is not a function

Step-by-step explanation:

because the element 2 has not ot unique image

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work out the area of a circle with diameter 1.8cm. Take <img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" al

ankoles [38]

Area of a circle is pi x r ^2

R = diameter/2

R = 1.8/2 = 0.9

Area = 3.142 x 0.9^2

Area = 2.5 square cm.

8 0

2 years ago

If the acceleration of an object is given by dv/dt = −2v, Find the position function s(t) if v(0) = 7 and s(0) = 0.

kirill [66]

Answer:

Step-by-step explanation:

Given that acceleration of an object is

$\frac{dv}{dt} =-2v\\\frac{dv}{v} =-2dt\\ln v = -2t+C\\$

is the solution to the differential equation

Since v(0) =7

we get ln 7 = C

Hence $lnv = -2t+ln 7\\v=7e^{-2t}$

since velocity is rate of change of distance s we have

$v=\frac{ds}{dt} =7e^{-2t}\\s= [tex]s(t) =\frac{-7}{2} (e^{-2t})+C)[$

substitute t=0 and s=0

$C=7/2$

So solution for distance is

$s(t) =\frac{-7}{2} (e^{-2t}-1)$

4 0

3 years ago

Evaluate 2 ∙ (8 + 4) using the steps of order of operations.

Natalka [10]

Step-by-step explanation:

Follow PEMDAS

$2 ∙ (8 + 4)$

P: Parentheses

E : Exponents

M: Multiplication

D: Division

A: Addition

S: Subtraction

$2 \cdot \: (12) \\ = 2 \times 12 \\ 24$

Question 2

$15 + 6 \times 3 \\ 15 + (6 \times 3) \\ 15 + 18 \\ = 33$

7 0

2 years ago

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Expand 2(7x - 1) please

vlada-n [284]

Answer:

14x - 2

Step-by-step explanation:

2(7x - 1)

Distribute the 2

2*7x - 2*1

14x - 2

6 0

3 years ago

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Why do you think items that come in a larger quantity cost less per unit

MAXImum [283]

They cost less because there are more items in stock meaning that there isn't a limit here is another way of thinking if there are less Items then they can charge you more per item because they know you are gonna want it but if there are tons of that one item they there kinda like eh then you think oh I can live without that....... Hope this helps

7 0

2 years ago

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