Answer:
The answer is the option C
cube root of 
Step-by-step explanation:
Remember that
![a^{\frac{x}{y}} =\sqrt[y]{a^{x}}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7Bx%7D%7By%7D%7D%20%3D%5Csqrt%5By%5D%7Ba%5E%7Bx%7D%7D)
in this problem we have
therefore
![2^{\frac{4}{3}} =\sqrt[3]{2^{4}}=\sqrt[3]{16}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B4%7D%7B3%7D%7D%20%3D%5Csqrt%5B3%5D%7B2%5E%7B4%7D%7D%3D%5Csqrt%5B3%5D%7B16%7D)
Answer:
Answer:
17 seedlings
Step-by-step explanation:
Given;
The seedlings are at an equal distance in a straight line.
Distance between 3rd seedling and 5th seedling = 9/10 m
So, distance between 3rd seedling and 4th seedling = 9/10 ÷ 2 = 9/20 m
So, the distance between two seedlings in a line = 9/20 m
The given distance between 2nd seedling and the last seedling = 6 3/4 m = 27/4 m
9514 1404 393
Answer:
382 square units
Step-by-step explanation:
The central four rectangles down the middle of the net are 9 units wide, and alternate between 8 and 7 units high. Then the area of those four rectangles is ...
9(8+7+8+7) = 270 . . . square units
The rectangles making up the two left and right "wings" of the net are 8 units high and 7 units wide, so have a total area of ...
2×(8)(7) = 112 . . . square units
Then the area of the figure computed from the net is ...
270 +112 = 382 . . . square units
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<em>Additional comment</em>
You can reject the first two answer choices immediately, because they are odd. Each face will have an area that is the product of integers, so will be an integer. There are two faces of each size, so <em>the total area of this figure must be an even number</em>.
You may recognize that the dimensions are 8, 8+1, 8-1. Then the area is roughly that of a cube with dimensions of 8: 6×8² = 384. If you use these values (8, 8+1, 8-1) in the area formula, you find the area is actually 384-2 = 382. That area formula is A = 2(LW +H(L+W)).
Answer:
xvideos
Step-by-step explanation:
