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3 years ago

Please I need help. you will get points

Mathematics

1 answer:

iragen [17]3 years ago

7 0

Answer:

t(32) = 94

Step-by-step explanation:

a. I think s is the independent variable

b I think t or t(s) is the dependent variable since the total amount of money depends on how many treats are sold.

t(32) = 30 + 2(32)

t(32) = 30 + 64

t(32) = 94

I'm a little unsure on the dependent and independent variable but I know the function is correct.

Hope this helps :)

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Peter is trying to buy fencing for the perimeter of his garden. His garden is in the shape of a rectangle with a length of 2(x+6

RideAnS [48]

Given dimensions of a rectangular garden are:

length = 2(x+6) feet

width = 3.5x feet

using the distributive property on length we get, length = 2x+12

Perimeter of a rectangle is 2(length+width)

So, P = 2(2x+12+3.5x)

Solving it we get,

P = 2(5.5x +12) ..............adding like terms

P = $(2\times5.5)+(2\times12)$ .............multiplying and adding

P = 11x+24

So, perimeter is 11x+24 feet. This value of fencing will be needed.

4 0

3 years ago

A distance AB is observed repeatedly using the same equipment and procedures, and the results, in meters, are listed below: 67.4

skad [1K]

Answer:

a) $\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401$

b) The sample deviation is calculated from the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

$\sigma =0.00319$

Step-by-step explanation:

For this case we have the following dataset:

67.401, 67.400, 67.402, 67.396, 67.406, 67.401, 67.396, 67.401, 67.405, and 67.404

Part a: Determine the most probable value.

For this case the most probably value would be the sample mean given by this formula:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

And if we replace we got:

$\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401$

Part b: Determine the standard deviation

The sample deviation is calculated from the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

$\sigma =0.00319$

3 0

4 years ago

In 1995, Derek Jeter's batting average was 0.250; in 1996, his batting average was 0.314. David Justice's batting average in 199

belka [17]

Answer:

The correct option is;

Simpson Paradox

Step-by-step explanation:

The phenomenon whereby particular trends are prevalent in small data portions but are not evident or an inverse trend is observe when the portions are joined together is known as Simpson's paradox.

Whereby the data for calculating the bating averages as found online are given as follows;

Season, Derek Jeter David Justice

1995, 12/48 = 0.250 104/411 ≈ 0.253

1996, 183/582 ≈ 0.314 45/140 ≈ 0.321

The overall hits to the overall bats ratio are;

, (183 + 12)/(582 + 48) ≈0.310 (104+45)/(411+140) = 0.27

Which shows that Derek Jeter's overall average was better than Justice's average

7 0

3 years ago

Please answer quickly with explanation. I am in need of major help. PLEASE NO FILE DOWNLOADS EITHER!!

Natali5045456 [20]

I am not sure but I think it’s b

7 0

3 years ago

Sue Mitchell weighed 8 lb. 13 oz. when she was born. She now weighs 93 lb. 5

ra1l [238]

Answer:

Weight gain = 84 lb 5 oz

Average weight gain = 6 lb 5 oz

Step-by-step explanation:

lb means pounds

16 oz = 1 pound

Convert the weight to pounds

Weight when she was born = 8 lb. 13 oz

= 8 pounds + 0.8125 pounds

= 8.8125 pounds

Present weight = 93 lb. 5

= 93 pounds + 0.3125 pounds

= 93.3125 pounds

How much has she gained since birth

Weight gain = Present weight - Weight when she was born

= 93.3125 pounds - 8.8125 pounds

= 84.5 pounds

= 84 lb 5 oz

Weight gain = 84 lb 5 oz

what has been her average weight for each year if she is 13 year old

Average weight gain = Weight gain / 13

= 84.5 pounds / 13

= 6.5 pounds

= 6 lb 5 oz

Average weight gain = 6 lb 5 oz

8 0

2 years ago

Please I need help. you will get points ​

Please I need help. you will get points