I
tan(32)x21=13mm
j
7.32/cos(66)=17.9cm
k
tan(34)x26.8=18m
i
23.9/tan(49)=20.7km
:)Good luck in Math
This is a division problem. You can use the standard algorithm of 128/ 5. Or you can create equal groups (draw five circles) and count out eggs until you distribute them all. I would start with 20 in each circle. That would be 20+ 20+ 20+ 20+ 20= 100 Then think 128-100= 28 Next count by 5's. 5+ 5+ 5+ 5+ 5= 25 Then think what is 28-25= 3 so 128/ 5= 25 with a reminder of 3 eggs left over.
For the selection to be 10, there has to be at least 3 girls. So there's a 1/4 chance of 3 girls picked, 1/4 4 girls, 1/4 5 girls and 1/4 6 girls. Because the sum of people has to be 10, if 4 girls are picked, to make 10 people there is a 1/1 chance of 6 boys. 1/4 * 1/1 = 1/4. So 1/4 chance of 4 girls and 6 boys
Answer:
5 and 0 between 250 and 300
As far as my math can tell the bigger one has a hypotnuse length of 8 whereas the smaller anes length is about 1 1/2
