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igor_vitrenko [27]
4 years ago
9

Can you help me with this problem?​

Mathematics
1 answer:
hjlf4 years ago
4 0
The answer is going to be A
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I would really really appreciate some help on this... brainliest to whoever can help?..
Lady bird [3.3K]

Answer:

=2 i think srry if i get it wrong

Step-by-step explanation:

4 0
3 years ago
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Someone please help and explain
Whitepunk [10]

okay so that would be a 1

because of the Rules of Zero

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4 years ago
(vii) log32 8=m<br> Again please
KonstantinChe [14]

Answer:

log_(32)8= 3/5

Step-by-step explanation:

Log_(32)8 = m

write is as

32^m=8

(2^5)^m = 2^3

2^5m = 2^3

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

5m = 3

divide 5 on both sides to remove it from m

m= 3/5

Hope this helps!

3 0
3 years ago
Solve. Good luck! Please do not try to google this.
Elena L [17]
\frac{x^{2} + x - 2}{6x^{2} - 3x} = \sqrt{2x} + \frac{3x^{2}}{2}
\frac{x^{2} + 2x - x - 2}{3x(x) - 3x(1)} = \frac{2\sqrt{2x}}{2} + \frac{3x^{2}}{2}
\frac{x(x) + x(2) - 1(x) - 1(2)}{3x(x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}
\frac{x(x + 2) - 1(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}
\frac{(x - 1)(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}
\frac{(x - 1)(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}
3x(2x - 1)(2\sqrt{2x} + 3x^{2}) = 2(x + 2)(x - 1)
3x(2x(2\sqrt{2x} + 3x^{2}) - 1(2\sqrt{2x} + 3x^{2}) = 2(x(x - 1) + 2(x - 1))
3x(2x(2\sqrt{2x}) + 2x(3x^{2}) - 1(2\sqrt{2x}) - 1(3x^{2})) = 2(x(x) - x(1) + 2(x) - 2(1)
3x(4x\sqrt{2x} + 6x^{3} - 2\sqrt{2x} - 3x^{2}) = 2(x^{2} - x + 2x - 2)
3x(4x\sqrt{2x} - 2\sqrt{2x} + 6x^{3} - 3x^{2}) = 2(x^{2} + x - 2)
3x(4x\sqrt{2x}) - 3x(2\sqrt{2x}) + 3x(6x^{3}) - 3x(3x^{2}) = 2(x^{2}) + 2(x) - 2(2)
12x^{2}\sqrt{2x} - 6x\sqrt{2x} + 18x^{4} - 9x^{3} = 2x^{2} + 2x - 4
12x^{2}\sqrt{2x} - 6x\sqrt{2x} = -18x^{4} + 9x^{3} + 2x^{2} + 2x - 4
6x\sqrt{2x}(2x) - 6x\sqrt{2x}(1) = -9x^{3}(2x) - 9x^{3}(-1) + 2(x^{2}) + 2(x) - 2(2)
6x\sqrt{2x}(2x - 1) = -9x^{3}(2x - 1) + 2(x^{2} + x - 2)
5 0
4 years ago
Write 400+5 in standard form
Vlada [557]
400+5 =405 is the answer
3 0
3 years ago
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