Can you help me with this problem?

The graph plots four equations, A, B, C, and D: Line A joins ordered pair negative 6, 16 and 9, negative 4. Line B joins ordered

Margaret [11]

Answer:

The pair of equations which has (2,12) as its solution is,

equation B and equation C.

Step-by-step explanation:

According to the question,

equation of line A is $\frac {y - 16}{x + 6} = \frac {16 + 4}{-6 - 9}$

or, $\frac {y - 16}{x + 6} = \frac {-4}{3}$

or, $3y - 48 = -4x - 24$

or, 3y + 4x = 24 ------------------(1)

Now, the point (2, 12) doesn't satisfy (1). Hence, (2,12) is not a solution for the line A.

Equation of line B is, $\frac {y - 20}{x + 2} = \frac {20 - 0}{-2 - 8}$

or, $\frac {y - 20}{x + 2} = -2$

or, $y - 20 = -2x - 4$

or, y + 2x = 16 -----------------------------(2)

The point (2,12) is satisfied by (2). Hence, (2, 12) is a solution for line B.

Equation of line C is, $\frac {y + 6}{x + 7} = \frac {20 + 6}{6 + 7}$

or, $\frac {y + 6}{x + 7} = 2$

or, y + 6 = 2x + 14

or. y - 2x = 8 -----------------------------------(3)

The point (2, 12) is satisfied by (3). Hence, (2 , 12) is a solution for the line C.

Equation of line D is, $\frac {y - 20}{x - 7} =\frac {20 + 7}{7 - 0}$

or, $\frac {y - 20}{x - 7} = \frac {27}{7}$

or, 7y - 140 = 27x - 189

or, 7y - 27x = -49----------------------------------------(4)

The point (2, 12) is not satisfied by (4). hence, (2, 12) is not a solution of the line D

Hence, the pair of equations which has (2,12) as its solution is,

equation B and equation C.

6 0

3 years ago

Please, somebody, solve this quick and reply with step by step explanation AND provide all steps of working!

Alexxx [7]

Answer:

For a trapezium of height H, parallel side 1 X, and parallel side 2 Y, the area is:

A = (1/2)*H*(X + Y)

with this we can complete the table.

a)

Here we know:

X = 7cm

Y = 11cm

H = 6cm

Then: A = (1/2)*6cm*(7cm + 11cm) = 54 cm^2

b)

Here we know:

X = 8 m

Y = 10 m

A = 126 m^2

Then:

126 m^2 = 0.5*H*(8m + 10m)

126 m^2 = H*9m

126 m^2/9m = H = 14m

Then the height of this trapezoid is 14m

c)

Here we know:

X = 5mm

H = 8mm

A = 72 mm^2

Then:

72 mm^2 = 0.5*8mm*(5mm + Y)

72 mm^2 = 4mm*(5mm + Y)

72mm^2/4mm = 5mm + Y

18 mm = 5mm + Y

18mm - 5mm = Y

13 mm = Y

Then the parallel side 2 is 13 mm long.

7 0

3 years ago

I don't know how to solve it

kotykmax [81]

I hope this helps you

8 0

3 years ago

Students in Mrs. Doyle's classes use 3/4 of a bottle of hand sanitizer every week. Which expression can be used to find how many

vampirchik [111]

Answer:

A. 12 x 3/4

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Julia is allowed to watch no more than 5 hours of television a week. So far this week, she has watched 1.5 hours. Write and solv

mojhsa [17]

Answer:

The inequality to show how many hours of television Julia can still watch this week can be given as:

⇒ $x+1.5\leq 5$

where $x$ represents he number of hours of television that Julia can still watch this week

On solving for $x$ , we get

$x\leq3.5$

Thus, Julia can still watch no more than 3.5 hours of television this week.

Step-by-step explanation:

Given:

Julia is allowed to watch television no more than 5 hours a week.

She has already watched 1.5 hours

To write and solve an inequality to show how many hours of television Julia can still watch this week.

Solution:

Let the number of hours of television that Julia can still watch this week be = $x$

Number of hours already watched = 1.5

Total number of hours of watching television this week would be given as:

⇒ $x+1.5$

It is given that Julia is allowed to watch no more than 5 hours of television in a week.

Thus, the inequality can be given as:

⇒ $x+1.5\leq 5$

Solving for $x$

Subtracting both sides by 1.5

$x+1.5-1.5\leq 5-1.5$

$x\leq3.5$

Thus, Julia can still watch no more than 3.5 hours of television this week.

6 0

3 years ago

Can you help me with this problem?​

Can you help me with this problem?