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mixer [17]
3 years ago
12

A bicycle tire has a radius of 0.23 m. The tire spins at a constant speed with a centripetal acceleration of 42 m/s2. What is th

e tangential speed of the tire?
Physics
2 answers:
Marianna [84]3 years ago
8 0

Answer:

A on Edge

Explanation:

zavuch27 [327]3 years ago
4 0
A = vt^2/r
vt^2 = a × r
vt = √(a × r)
vt = √(42 m/s^2 × 0.23 m)
vt = √9.66 m^2/s^2
vt = 3.108 m/s
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A 26.2-kg dog is running northward at 3.02 m/s, while a 5.30-kg cat is running eastward at 2.74 m/s. Their 65.1-kg owner has the
REY [17]

Answer:

Angle with the +x axis is θ = 79.599degree

Then the velocity of owner = 1.235m/s

Explanation:

Given that the mass of dog is m1 =26.2 kg

velocity of dog is u1 = 3.02 m/s (north)

mass of cat is m2 = 5.3 kg

velocity is u2 = 2.74 m/s (east )

Mass of owner is M = 65.1 kg

Consider the east direction along +x axis andnorth along +y

momentum of dog is Py = m1 x u1

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momentum of cat is Px = m2 x u2

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Then the net magnitude of momentum is P = (Px2 + Py2)1/2

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Angle with the +x axis is θ =tan-1(Py / Px ) = 79.599 degree

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Calculate the maximum capillary rise/fall of mercury in a 0.5 mm radius glass capillary. Assume that the surface tension for mer
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