It's C i believe. To solve it we just take 20 and divide it by 2. Which gives us the average of 10 m/s
-Steel jelly
Answer:
88 m/s
Explanation:
To solve the problem, we can use the following SUVAT equation:
![v^2-u^2=2ad](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2ad)
where
v is the final velocity
u is the initial velocity
a is the acceleration
d is the distance covered
For the car in this problem, we have
d = 484 m is the stopping distance
v = 0 is the final velocity
is the acceleration
Solving for u, we find the initial velocity:
![u=\sqrt{v^2-2ad}=\sqrt{-2(8.0)(484)}=88 m/s](https://tex.z-dn.net/?f=u%3D%5Csqrt%7Bv%5E2-2ad%7D%3D%5Csqrt%7B-2%288.0%29%28484%29%7D%3D88%20m%2Fs)
To solve this problem it is necessary to apply the concepts related to acceleration due to gravity, as well as Newton's second law that describes the weight based on its mass and the acceleration of the celestial body on which it depends.
In other words the acceleration can be described as
![a = \frac{GM}{r^2}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7BGM%7D%7Br%5E2%7D)
Where
G = Gravitational Universal Constant
M = Mass of Earth
r = Radius of Earth
This equation can be differentiated with respect to the radius of change, that is
![\frac{da}{dr} = -2\frac{GM}{r^3}](https://tex.z-dn.net/?f=%5Cfrac%7Bda%7D%7Bdr%7D%20%3D%20-2%5Cfrac%7BGM%7D%7Br%5E3%7D)
![da = -2\frac{GM}{r^3}dr](https://tex.z-dn.net/?f=da%20%3D%20-2%5Cfrac%7BGM%7D%7Br%5E3%7Ddr)
At the same time since Newton's second law we know that:
![F_w = ma](https://tex.z-dn.net/?f=F_w%20%3D%20ma)
Where,
m = mass
a =Acceleration
From the previous value given for acceleration we have to
![F_W = m (\frac{GM}{r^2} ) = 600N](https://tex.z-dn.net/?f=F_W%20%3D%20m%20%28%5Cfrac%7BGM%7D%7Br%5E2%7D%20%29%20%3D%20600N)
Finally to find the change in weight it is necessary to differentiate the Force with respect to the acceleration, then:
![dF_W = mda](https://tex.z-dn.net/?f=dF_W%20%3D%20mda)
![dF_W = m(-2\frac{GM}{r^3}dr)](https://tex.z-dn.net/?f=dF_W%20%3D%20m%28-2%5Cfrac%7BGM%7D%7Br%5E3%7Ddr%29)
![dF_W = -2(m\frac{GM}{r^2})(\frac{dr}{r})](https://tex.z-dn.net/?f=dF_W%20%3D%20-2%28m%5Cfrac%7BGM%7D%7Br%5E2%7D%29%28%5Cfrac%7Bdr%7D%7Br%7D%29)
![dF_W = -2F_W(\frac{dr}{r})](https://tex.z-dn.net/?f=dF_W%20%3D%20-2F_W%28%5Cfrac%7Bdr%7D%7Br%7D%29)
But we know that the total weight (F_W) is equivalent to 600N, and that the change during each mile in kilometers is 1.6km or 1600m therefore:
![dF_W = -2(600)(\frac{1.6*10^3}{6.37*10^6})](https://tex.z-dn.net/?f=dF_W%20%3D%20-2%28600%29%28%5Cfrac%7B1.6%2A10%5E3%7D%7B6.37%2A10%5E6%7D%29)
![dF_W = -0.3N](https://tex.z-dn.net/?f=dF_W%20%3D%20-0.3N)
Therefore there is a weight loss of 0.3N every kilometer.
It is the same if a white father and a white mother give birth to a black kid, so the mother accuses the father for having (let's say mating) with a black women.
Answer:
V = I×R
where -
V = potential difference across
I = current flowing in the circuit
R = Equivalent Resistance in the circuit