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Alenkasestr [34]
3 years ago
14

Which of the following is an example of speed? Question 8 options: A truck driving 15 miles per hour south. A cat running 5 mete

rs per minute. A bicyclist ridding 12 miles per hour east. A plane traveling at 15 miles
Physics
2 answers:
xxTIMURxx [149]3 years ago
7 0
The answer would be <u>a cat running at 5 meters per minute</u>.

Hope this helps :)
marusya05 [52]3 years ago
3 0
I think the answer is a plane traveling at fifteen miles

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You observe two stars over the course of a year (or more) and find that both stars have measurable parallax. (1 arc second is 1/
Ierofanga [76]

Answer:

Star X is much closer since it is at a distance 1 parsec from the Earth.

Explanation:

The angle due to the change in position of a nearby object against the background stars it is known as parallax.

The parallax angle can be used to find out the distance by means of triangulation. Making a triangle between the nearby star, the Sun and the Earth. This angle is gotten when the position of the object is measured in January and then in July according to the configuration of the Earth with respect to the Sun in those months.

The distance between the Earth and the Sun is 150000000 Km. That distance is also known as an astronomical unit (1AU).

The parallax angle can be defined in the following way:

\tan{p} = \frac{1AU}{d}    

Where d is the distance to the star.

p('') = \frac{1}{d}    (1)  

Equation (1) can be rewritten in terms of d:

d(pc) = \frac{1}{p('')} (2)

Equation (2) represents the distance in a unit known as parsec (pc).

Case of Star X (p('') = 1):

Using equation 2 the distance of star X can be known:

d(pc) = \frac{1}{1}

d(pc) = 1 pc

So, star X is at 1 parsec from Earth.

Case of Star Y (p('') = \frac{1}{2}):

d(pc) = \frac{1}{(\frac{1}{2})}

d(pc) = 2 pc

So, star Y is at 2 parsecs from the Earth.

Hence, star X is much closer.

Reminder:

Notice that in equation 2 the distance is inversely proportional to the parallax angle, so if the parallax angle decreases, the distance increases.

5 0
3 years ago
1. Calculate the power it takes for a 583 N student to climb up1.5 m stairs in 2.1 seconds. (find work first!)GivenFormulaSubsti
Tanzania [10]

Given data

*The given force is F = 583 N

*The given distance is s = 1.5 m

*The given time is t = 2.1 s

The formula for the power it takes for a 583 N student to climb up 1.5 m stairs in 2.1 seconds is given as

P=\frac{F\mathrm{}s}{t}

Substitute the known values in the above expression as

\begin{gathered} P=\frac{(583)(1.5)}{(2.1)} \\ =416.42\text{ W} \end{gathered}

Hence, the power it takes for a 583 N student to climb up 1.5 m stairs in 2.1 seconds is P = 416.42 W

3 0
1 year ago
Two objects A and B vertically thrown up with velocities 80m/s and 100m/s at two sec interval.where and when will they meet each
romanna [79]

Answer:

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Explanation:

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7 0
3 years ago
DONT ANSWER IF YOU DONT KNOW. For a person who is farsighted, what would they need to have a correct focal point?
fiasKO [112]
A) Convex Lens.... hope it helps :)
5 0
3 years ago
2) A molecule of hydrochloric acid HCl contains one atom of hydrogen and *
Dimas [21]

Answer:

3

Explanation:

because I put that it's was right

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