Answer: BeO
Explanation:
percent by mass of oxygen
percent by mass of oxygen in BeO
percent by mass of oxygen in MgO
percent by mass of oxygen in CaO
percent by mass of oxygen in SrO
I think the correct answer from the choices listed above is option B. <span>24 mL of Mg burn in 32 mL O2 to produce 56 mL of MgO </span>does not show the law of conservation of mass. Volumes cannot be added because there are volume effects when you add different substances. So, the reactants is not equal to the product.
1.22 mg is the same as .022 grams. One gram equals 1000 mg. Convert mg to grams by dividing mg by 1000mg/gm. Volume = mass over density. Volume equals .022 grams over .754 grams/cm3 which equals .029 or .03cm3. 2.weight in kg times gravity constant. Weight in newtons equals 10kg times 9.8m/s2 that equals 98 newtons.
Explanation:
The given balanced reaction is as follows.

It is given that mass of ammonium nitrate is 86.0 kg.
As 1 kg = 1000 g. So, 86.0 kg = 86000 g.
Hence, moles of
present will be as follows.
Moles of
= 
= 
= 1074.42 mol
Therefore, moles of
,
and
produced by 1074.42 mole of
will be as follows.
Moles of
= 
= 537.21 mol
Moles of
= 
= 1074.42 mol
Moles of
= 
= 2148.84 mol
Therefore, total number of moles will be as follows.
537.21 mol + 1074.42 mol + 2148.84 mol
= 3760.47 mol
According to ideal gas equation, PV = nRT. Hence, calculate the volume as follows.
PV = nRT
1 atm \times V = 3760.47 mol \times 0.0821 L atm/mol K \times 580 K[/tex] (as
= 307 + 273 = 580 K)
V = 179066.06 L
Thus, we can conclude that total volume of the gas is 179066.06 L.
All of these metals from cations, so they lost electrons when forming ions. The answer is D.