Bromide ions donates an electron in redox reactions.
<u>Explanation:</u>
- In these redox reactions, the halide ions like bromide donates a pair of electrons and acts as a reducing agents, but itself gets oxidized to bromine.
- In this process, the oxidation state of bromide ion is increased from -1 to 0 oxidation state, that is Br⁻ (-1) to Br₂ (0), thus reduces the compound and oxidizes by itself.
- Bromide ion is a strong reducing agent, thereby reduces sulfuric acid which changes to sulfur di oxide, but this doesn't happen in the case of chloride and fluoride ions as they are not having that much capacity like bromide and iodide ions.
Fossil fuels is the answer
Answer: The percentage by mass of sulphur in 
is 9.36%
Explanation:
Mass percent of an element is the ratio of mass of that element by the total mass expressed in terms of percentage.
Given: mass of sulphur = 32 g/mol
mass of = 342 g/mol
Putting in the values we get:
The percentage by mass of sulphur in is 9.36%
Answer is B, because CaSO3 only has one S
