Question

In PbO + 2HCl → PbCl2 + H20,13 g of lead oxide is

Answer 1

Answer:

HCl acts as an excess reagent

Explanation:

The reaction equation is;

PbO + 2HCl → PbCl2 + H20

Number of moles of PbO = 13g/223.2 g/mol = 0.058 moles

Since the mole ratio is 1:1, 0.058 moles of PbCl2 is produced

Number of moles of HCl = 6.4 g/36.5g/mol = 0.175 moles

2 moles of HCl yields 1 mole of PbCl2

0.175 moles yields 0.175 moles * 1/2

= 0.0875 moles of PbCl2

Hence; PbO yields the least number of moles of product so it is the limiting reactant and HCl is the reactant in excess