Answer:
HCl acts as an excess reagent
Explanation:
The reaction equation is;
PbO + 2HCl → PbCl2 + H20
Number of moles of PbO = 13g/223.2 g/mol = 0.058 moles
Since the mole ratio is 1:1, 0.058 moles of PbCl2 is produced
Number of moles of HCl = 6.4 g/36.5g/mol = 0.175 moles
2 moles of HCl yields 1 mole of PbCl2
0.175 moles yields 0.175 moles * 1/2
= 0.0875 moles of PbCl2
Hence; PbO yields the least number of moles of product so it is the limiting reactant and HCl is the reactant in excess
