Answer:exactly 28200 meters
Explanation:
the Axis Perpendicular to the Length and Passing through the Center. Take a uniform thin rod AB whose mass is M and length is l. YY’ axis passes through the center of the rod and perpendicular to the length of the rod. We have to calculate the moment of inertia about this axis. YY’.
Suppose, small piece dx is at a distance x from the YY' axis. Hence, mass of length dx is =(
l
M
)dx The moment of inertia of small piece about the YY' axis
dl=[(
l
M
)dx]x
2
Therefore, the moment of inertia of the complete rod about the YY' axis.
b) Moment of Inertia about the axis perpendicular to the the length and passing through the Corner If I
CD
is the moment of inertia about the axis CD perpendicular to the length of a thin rod and passing through the point A then, by theorem of parallel axis;
l
CD
=l
YY
′
+Md
2
=
12
Ml
2
+M(
2
l
)
2
l
CD
=
3
Ml
2
.........(2)
Answer:
a) 
b) T = 720.85N
Explanation:
With a balance of energy from the lowest point to its maximum height:
Solving for 
:
Centripetal acceleration is:
To calculate the tension of the rope, we make a sum of forces:
Solving for T:
T = 720.85N
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