Four members of a relay team evenly split the distance of a race. Each person ran more than 100 meters. Which inequality can be
used to represent d, the total distance the group ran? No links
1 answer:
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Total = Principal * [1 + (rate/n)]^n*years
Where "n" is the compounding periods per year
Total = 12,000 * (1+(.05/4))^(4*4)
Total = 12,000 * (1.0125)^(16)
Total = 12,000 * <span> <span> <span> 1.2198895477 </span> </span> </span> <span> </span>
Total = <span> <span> </span></span><span><span><span>14,638.67</span>
</span> </span>
Where "n" is the compounding periods per year
Total = 12,000 * (1+(.05/4))^(4*4)
Total = 12,000 * (1.0125)^(16)
Total = 12,000 * <span> <span> <span> 1.2198895477 </span> </span> </span> <span> </span>
Total = <span> <span> </span></span><span><span><span>14,638.67</span>
</span> </span>