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Bess [88]
3 years ago
13

Four members of a relay team evenly split the distance of a race. Each person ran more than 100 meters. Which inequality can be

used to represent d, the total distance the group ran? No links

Mathematics
1 answer:
Vadim26 [7]3 years ago
8 0
The total distance the group ran can be represented by d > 400 m

The total distance the group ran can be got by summing up all the individual distances ran by each athlete.
Let the distance the first athlete ran be x
from the question, we know that x >100 m
since all four athletes ran the same distance, the total distance run , d will be four times the distance ran by an athlete.
d > 4 X 100
d > 400 m
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At the Arctic weather station, a warning light turns on if the outside temperature is below -25 degrees Fahrenheit. Which inequa
Leya [2.2K]

Answer:

t≥-25

Step-by-step explanation:

this is becuaset ≥ -25 shows that it can not fall under -25, but can be equal to -25.

8 0
2 years ago
21 = − 6 x − 3 x + 4 + 4 x
horsena [70]

Answer:

x=-17/5

Step-by-step explanation:

1. Simplify  -6x-3x+4+4x−6x−3x+4+4x  to  -5x+4−5x+4.

21=−5x+4

2. Subtract 44 from both sides.

21−4=−5x

3. Simplify  21-4 to 17.

17=-5x

4. Divided both sides by -5.

-17/5=x

5. Switch sides.

x=-17/5

Hope this helps.

4 0
3 years ago
For all of the Following use the function LaTeX: P\left(x\right)\:=\:\left(x+3\right)^2+2 . My original vertex is
PolarNik [594]

Answer:

A) Q(x) = (x + 3)² + 5, and the vertex is (-3, 5)

B) R(x) = (x - 3)² + 2, and the vertex is (3, 2)

C) S(x) = (x - 1)² - 5, and the vertex is (1, -5)

Step-by-step explanation:

The given function is P(x) = (x + 3)² + 2

The given function is a parabolic function in vertex form, f(x) = a·(x - h)² + k, and vertex, (h, k)

By comparison, the vertex of the function P(x) = (x + 3)² + 2 is (-3, 2)

A) A function f(x) translated α units UP gives

f(x) (translated α units UP) → f(x) + α

A translation of the function 3 units UP is given by adding 3 to the given function as follows;

Q(x) = P(x) + 3

∴ Q(x) = (x + 3)² + 2 + 3 = (x + 3)² + 5

Q(x) = (x + 3)² + 5, and the vertex by comparison to f(x) = a·(x - h)² + k, and vertex, (h, k) is (-3, 5)

B) A function f(x) translated <em>b</em> units RIGHT gives;

f(x) translated <em>b</em> units right → f(x - b)

∴ P(x) = (x + 3)² + 2 translated 6 units RIGHT gives;

P(x) = (x + 3)² + 2 (translated 6 units RIGHT) → R(x) = (x + 3 - 6)² + 2 = (x - 3)² + 2

R(x) = (x - 3)² + 2, and the vertex by comparison is (3, 2)

C) A function translated α units DOWN and <em>b</em> units RIGHT is given as follows;

f(x) \ translated \ by\  \dbinom{b}{a} \rightarrow f(x - b) - a

Therefore, the given function, P(x) = (x + 3)² + 2, translated 7 units DOWN and 4 units RIGHT gives;

P(x) = (x + 3)^2 + 5 \ translated \ by\  \dbinom{4}{-7} \rightarrow P(x - 4) - 7 = S(x)

S(x) = P(x - 4) - 7 = (x + 3 - 4)² + 2 - 7 = (x - 1)² - 5

P(x) = (x + 3)^2 + 5 \ translated \ by\  \dbinom{4}{-7} \rightarrow (x - 1)^2 - 5= S(x)

S(x) = (x - 1)² - 5, and the vertex by comparison is (1, -5)

7 0
3 years ago
What Information is required
LenaWriter [7]

Answer:

BC=XY

Step-by-step explanation:

you know 2 angles. you need a side for ASA. BC and XY is the only one that would be included.

8 0
3 years ago
Read 2 more answers
Discuss the conditions under which P(A or B)= P(A) + P(B) is true
Andrews [41]
That condition is true if P(A) and P(B) are independent of one another. For example, if I was pulling marbles out of a bag, if I am replacing the marbles back after I pull one out, then P(A or B) = P(a)+P(B).
4 0
3 years ago
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