Owls are birds of prey. ... After an owl eats the small rodents, birds, and bugs that are a part of its nightly diet, its stomach cannot digest the fur, bones, teeth, feathers, and insect shells from that food. These “extra” parts are formed into a tight PELLET inside the owl and are then are later SPIT UP by the owl.
Answer:
Reactants.
Step-by-step explanation:
The equation for the reverse reaction is
Z + Q ⟶ X + Y; ΔH < 0
A negative ΔH indicates that the energy has been given off.
The products X + Y are at a <em>lower energy level</em> than the reactants Z + Q, and the excess energy has been <em>transferred to the surroundings</em>.
Answer:
Explanation:
pH = pKa + log [ CH₃COO⁻ ] / [CH₃COOH ]
5.36 = 4.86 + log [ CH₃COO⁻ ] / [CH₃COOH ]
log [ CH₃COO⁻ ] / [CH₃COOH ] = .5
[ CH₃COO⁻ ] / [CH₃COOH ] = 3.16
moles of CH₃COOH = .680 x .9 = .612 M
Let x mole of KOH is required
x /( .612 - x ) = 3.16
x = 1.933 - 3.16 x
x = .46488
.46488 moles of KOH will be required
volume required be V
v x 2.62 = .46488
v = .1774 L
= 177.4 mL
177.4 mL of 2.62 M KOH will be required .
Answer:
The mass of oxygen needed to be pumped in the aquarium is 10 g
Explanation:
Here the value of the degree of solubility of oxygen in water is sought
The solubility of oxygen in fresh water is approximately 1.22 × 10⁻³ mol·dm⁻³ which is equivalent to approximately 40 mg/L
The volume of water the aquarium holds = 250 L
The mass of oxygen required = The solubility of oxygen in water × (The volume of water in the aquarium)
Therefore, the mass of oxygen needed to be pumped in the aquarium = 40 mg/L × 250 L = 10,000 mg
1,000 mg = 1 g
∴ 10,000 mg = 10 g
The mass of oxygen needed to be pumped in the aquarium = 10,000 mg = 10 g.
I can’t answer the exact thing, but I know how to do it. One of the nitrogen bases always pairs with a different one, so once you know what pairs with what you just write it down. If you need more help just ask :) tip: one base will only join with a different one. One won’t join to multiple (from what I know as of now)
