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tresset_1 [31]
3 years ago
9

Which diagram shows a voltaic cell?

Chemistry
1 answer:
boyakko [2]3 years ago
6 0
Since you have not included the figures with the diagrams to select the right answer, I am going to explain the main differences that lead you to differentiate electrochemical cells.

There are four important terms needed to identify the electrochemical cells: electrolysis, electrochemical cells, electrolitc cells and voltaic cells.

1) Electrochemical cell: is a device that uses a chemical reaction (redox reaction) to produce electricity or that uses electricity to product a chemical reaction.

2) Electrolysis: is the production of a chemical reaction using electricity.

3) Electroltic cell: is one of the two types of electrochemical cell. It is that in which electricity is used  to produce the chemical reaction, i.e. where electrolysis happens. For example, the decomposition of sodium chloride brines is done in an electrolitic cell.

4) Galvanic cell: is the other type of electrochemical cell. It is that in which chemical reactions (redox reactions) produce electricity. The battery of the car is an example of a galvanic cell.

Here you are asked to identify which diagram shows a voltaic cell.So, you need to lool at:

- a redox reaction is happening

- this redox reaction is producing electricity (not that the electricity is producing the reaction)

Remember that a redox reaction is where some atoms are being reduced (gaining electros) and others are being oxidized (losing electrons).

Tha information will let you to choose the righ diagram.
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Which factor is generally responsible for high melting points?
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A. High intermolecular forces of attraction. If there are high intermolecular forces, the molecules will need large energies to escape into the liquid. The substance will nave a high melting point.

The other options are <em>incorrect </em>because they are <em>weak force</em>s. They would cause <em>low melting points</em>.

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3 years ago
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The two naturally occuring isotopes of antimony are 121Sb (57.21%) and 123Sb (42.79%), with isotopic masses of 120.904 and 122.9
emmasim [6.3K]

Answer:

The average atomic weight = 121.7598 amu

Explanation:

The average atomic weight of natural occurring antimony can be calculated as follows :

To calculate the average atomic mass the percentage abundance must be converted to decimal.

121 Sb has a percentage abundance of 57.21%, the decimal format will be

57.21/100 = 0.5721 . The value is the fractional abundance of 121 Sb .

123 Sb has a percentage abundance of 42.79%, the decimal format will be

42.79/100 = 0.4279. The value is the fractional abundance of 123 Sb .

Next step is multiplying the fractional abundance to it masses

121 Sb = 0.5721 × 120.904 = 69.169178400

123 Sb = 0.4279 × 122.904 = 52.590621600

The final step is adding the value to get the average atomic weight.

69.169178400 + 52.590621600 = 121.7598 amu

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