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4 years ago

How many electrons in an atom can share the quantum numbers n = 1, m subscript l = 0? A. 1 B.2 C.3 D.6

Chemistry

1 answer:

Kisachek [45]4 years ago

6 0

I believe it would be c: 3 because you can have the numbers -1,0,1.

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What is the molar mass of Ca(ClO4)2? 171.6 g/mol 203.6 g/mol 239.0 g/mol 279.1 g/mol

Lady_Fox [76]

Answer:

239.0 g/mol

Explanation:

The molar mass of a compound is the sum of all the molar masses of all the individual elements present in the compound.

The molar mass of Ca(ClO4)2 can calculated as follows:

= 40 + 2[ 35.5 + (16x4)]

40 + 2[ 35.5 + 64]

40 + 2[99.5]

40 + 199

239g/mol

7 0

4 years ago

How many oxygen atoms are in 7.25g of calcium nitrate

Yuki888 [10]

Answer:

The answer to this question is approximately equal to 1.6 ×

$1.6 \times {10}^{23} atom \: o$

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3 years ago

Identify a false statement about how to protect iron from corrosion.

DIA [1.3K]

False: to protect iron from corrosion, keep it near moistureband oxygen.

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3 years ago

Cosity a letter to our mother

kotykmax [81]

An answer befitting your question…

Hi mom, I’m having troubles with my teachers. They are cruel to me and I cannot concentrate. I think if we changed schools it would be much better. Thank you mom.

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3 years ago

Yttrium-90, Y90 , is a radioactive isotope used in the treatment of liver cancer. The half‑life of Y90 is 2.67 days. If a dose w

adelina 88 [10]

It takes 16.02 days for the activity of Y90

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.

Usually radioactive elements have an unstable atomic nucleus.

The main particles are emitted by radioactive elements so that they generally decay are alpha (α), beta (β) and gamma (γ) particles

General formulas used in decay:

$\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{T/t\frac{1}{2} }}}$

T = duration of decay

t 1/2 = half-life

N₀ = the number of initial radioactive atoms

Nt = the number of radioactive atoms left after decaying during T time

No=192 μCi

Nt=3 μCi

t1/2=2.67 days

$\tt 3=192(\dfrac{1}{2})^{\dfrac{T}{2.67}}\\\\\dfrac{1}{64}=\dfrac{1}{2}^{\dfrac{T}{2.67}}\\\\\dfrac{1}{2}^6=\dfrac{1}{2}^{\dfrac{T}{2.67}}\\\\6=\dfrac{T}{2.67}\\\\T=16.02~days$

5 0

3 years ago