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natka813 [3]
3 years ago
8

If mass and velocity are unknown when using de Broglie's wavelength formula, what alternative value must we have to successfully

determine the wavelength
Physics
1 answer:
mojhsa [17]3 years ago
5 0

Answer:

The particle momentum, p

Explanation:

A particle's de Broglie's wavelength is an indication of the scale in length where the particle's wave-like properties are important. The symbol of de Broglie wavelength is λ or \lambda _{dB} given as follows;

The de Broglie's wavelength formula is given as follows;

\lambda = \dfrac{h}{m \cdot v} = \dfrac{h}{p}

Where;

λ = The wavelength of the particle in meters

v = The velocity of the particle in meters/seconds

m = The mass of the particle in kilograms

p = The momentum of the particle

h = Planck's constant = 6.626 × 10⁻³⁴ J/Hz

Therefore, the alternative value that we must have to successfully determine the wavelength if the mass and velocity are unknown, is the momentum, p of the particle.

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Assuming this is a distance time graph( ignore the speed time title) assume metres on vertical scale. describe in as much detail
riadik2000 [5.3K]

Answer:

The journey started from point A, with a speed of  1 m/s for 10 seconds after which the it became stationary at 10 meters from the start point, for 10 seconds. The journey continued at a higher speed of 2 m/s for 5 seconds and halted (became stationary) again at 20 meters which was the maximum distance reached from the start point

The return journey to the start point started at the 20 meter mark and lasted for 5 seconds, at a speed of 4 m/s

The total distance travelled during the journey from the start point A to the final point B is 40 m

Explanation:

From the start point A to point B, we have;

The speed from A to B = 10 m/(10 s) = 1 m/s

The distance traveled from A to B = 10 m

The time it takes to move from A to B = 10 seconds

From the point B to point C, we have;

The distance traveled from B to C = 0 m, (stationary)

The time it remains at point B distance from the start point = 10 seconds

The speed between point B to C = 0 m/(10 s) = 0 m/s

From the point C to point D, we have;

The distance traveled from C to D = 10 m

The time it takes to move from C to D = 5 seconds

The speed between point C and D = 10 m/(5 s) = 2 m/s

From the point D to point E, we have;

The distance traveled from D to E = 0 m, (stationary)

The time it remains at point D distance from the start point = 10 seconds

The speed between point D to E = 0 m/(10 s) = 0 m/s

From the point E to point F, we have;

The distance traveled from E to F = 20 m (return journey starts at point E)

The time it takes to move from E to F = 5 seconds

The speed between point E to F = 20 m/(5 s) = 4 m/s (Return journey)

Therefore, the journey started from point A, with a speed of  1 m/s for 10 seconds after which the it became stationary at 10 meters from the start point, for 10 seconds. The journey continued at a higher speed of 2 m/s for 5 seconds and halted (became stationary) again at 20 meters which was the maximum distance reached from the start point

The return journey to the start point started at the 20 meter mark and lasted for 5 seconds, at a speed of 4 m/s

The total distance moved, 'd', to and from the start point with reference to the graph is given as follows;

d = (From A to B) 10 m + (From B to C) 0 m + (From C to D) 10 m + (From D to E) 0 m + (From E to F) 20 m = 40 m

The total distance travelled in the journey is 40 m

The total displacement, \underset{d}{\rightarrow} = 10 m + 10 m - 20 m = 0 m

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3 years ago
Why do you think sound travels faster in steel than it does in wood? (Hint: Think about the densities of the two materials, and
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Answer:

If sound waves of the same energy were passed through a block of wood and a block of steel, which is more dense than the wood, the molecules of the steel would vibrate at a slower rate. Sound moves faster through denser air because the molecules are closer together in dense air and sound can be more easily passed on.

Explanation:

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the hot gas lines need to be insulated? A never B always C if they are exposed to cold temperatures that could cause the refrige
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While riding a multispeed bicycle, the rider can select the radius of the rear sprocket that is fixed to the rear axle. The fron
gtnhenbr [62]

Answer:

2.9 cm

Explanation:

Assuming that the rear wheel has a radius of 0.330 m

Given that

r(a) = 12 cm -> 0.12 m

w(a) = 0.6 rev/s -> 3.77 rad/s

v = 5 m/s

r(w) = 0.330 m

The speed on any point on the rim at the sprocket in the front is

v(a) = w(a).r(a) = 3.77 * 0.12 = 0.4524 m/s

Also,

v(a) = speed at any point on the chain

v(b) = speed at any point on the rim of the rear sprocket

v(a) = v(b)

where v(b) = w(b).r(b)

Recall that the speed at any point on the rear wheel is v, where

v = w(b).r(w)

5 = w(b) * 0.330

w(b) = 5/0.330

w(b) = 15.15 rad/s

On substituting this in the equation, we have

v(b) = w(b).r(b).

Remember also, that v(a) = v(b), so

0.4524 = 15.15 * r(b)

r(b) = 0.4524 / 15.15

r(b) = 0.029 m -> 2.9 cm

Therefore, the radius of the rear sprocket needed is 2.9 cm

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Which describes Einstein’s idea of space and time?
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Time and space are both relative
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3 years ago
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