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vladimir2022 [97]
2 years ago
14

when a metal sphere is dropped in to a tall cylinder containing liquid its acceleration is g÷2 (gravity over 2) show that : dens

ity of metal =2density of liquid​
Physics
1 answer:
Kryger [21]2 years ago
6 0

The density of the metal sphere is 2 times the density of the liquid as proved.

<h3>Net upward force acting on the metal sphere</h3>

The net upward force acting on the sphere as it is dropped into the liquid is calculated as follows;

F =  σVg - ρVg

ma =  σVg - ρVg  

where;

  • ρ is density of the liquid
  • σ is the density of the metal
  • a is acceleration of the metal

σV(a) =  σVg  - ρVg

σ(a) = σg  - ρg

σ(g/2) = σg -  ρg  

g(σ/2) = g(σ -  ρ)

σ/2 = σ -  ρ

σ/2 - σ = -  ρ

-σ/2 = -  ρ

σ = 2ρ

Thus, the density of the metal sphere is 2 times the density of the liquid as proved.

Learn more about density here: brainly.com/question/1354972
#SPJ1

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A child picks a ball up from the ground, then places it on a table. The ball rolls on the
crimeas [40]

Answer:

A- The ball has both kinetic and potential energy,

Explanation:

kinetic energy by virtue of its motion.

potential energy by virtue of its position. (It could roll off the edge of the tabel and convert gravity potential energy to kinetic energy)

6 0
3 years ago
The dogs of four-time Iditarod Trail Sled Dog Race champion Jeff King pull two 100-kg sleds that are connected by a rope. The sl
azamat

Answer:

Part a)

a = 2.4 m/s^2

Part b)

F = 120 N

Explanation:

Two sleds are connected by a rope

mass of each sled is given as

m = 100 kg

now we know that dog exert pulling force on the rope connected to first sled

F = 240 N

Part a)

By newton's first law we know that

F = (m + m)a

240 = (100 + 100)a

a = \frac{240}{100}

a = 2.4 m/s^2

Part b)

As we know that force between two ropes will pull the sled behind

so we will have

F = ma

F = 100(1.20)

F = 120 N

7 0
3 years ago
Read 2 more answers
A block slides to a stop as it goes 47 m across a level floor in a time of 6.35 s. a) What was the initial velocity? b) What is
UNO [17]

Answer :

(a) The initial velocity is, 14.8 m/s

(b) The acceleration is, -2.33m/s^2

Explanation :

By the 1st equation of motion,

v=u+at     ...........(1)

where,

v = final velocity = 0 s

u = initial velocity

t = time = 6.35 s

a = acceleration

The equation 1 will be:

0=u+a(6.35}

u=-6.35a       ..........(2)

By the 2nd equation of motion,

s=ut+\frac{1}{2}at^2     ...........(3)

where,

s = distance = 47 m

Now substitute equation 2 in 3, we get:

47=(-6.35a)\times (6.35)+\frac{1}{2}\times a\times (6.35)^2

By solving the term, we get:

a=-2.33m/s^2

The acceleration is, -2.33m/s^2

Now we have to calculate the initial velocity.

Using equation 2, we gte:

u=-6.35a

u=-6.35s\times (-2.33m/s^2)

u=14.8m/s

The initial velocity is, 14.8 m/s

5 0
3 years ago
A lightweight string is wrapped several times around the rim of a small hoop. If the free end of the string is held in place and
MariettaO [177]

Answer:

Explanation:

Let T be the tension

For linear motion of hoop downwards

mg -T = ma , m is mass of the hoop . a is linear acceleration of CG of hoop .

For rotational motion of hoop

Torque by tension

T x R ,      R is radius of hoop.

Angular acceleration be α,

Linear acceleration a = α R

So TR = I  α

= I  a / R

a = TR² / I

Putting this value in earlier relation

mg -T = m TR² / I

mg = T ( 1 + m R² / I )

T = mg / ( 1 + m R² / I )

mg / ( 1 + R² / k² )

Tension is less than mg or weight because denominator of the expression is more than 1.

5 0
3 years ago
What is the temperature of a system in thermal equilibrium with another system made up of water and steam at one atmosphere of p
Evgen [1.6K]

Full Question:

What is the temperature of a system in thermal equilibrium with another system made up of water and steam at one atmosphere of pressure?

A) 0°F

B) 273 K

C) 0 K

D) 100°C

E) 273°C

Answer:

The correction Option is D) 100°C

Explanation:

The temperature above is referred to as the critical point.

it is the highest temperature and pressure at which water (which has three phases - liquid, solid, and gas) can exist in vapor/liquid equilibrium. If the temperature goes higher than 100 degrees celsius, it cannot remain is liquid form regardless of what the pressure is at that point.

There is also a condition under which water can exist in its three forms: that is  

- Ice (solid)

- Liquid (fluid)

- Gas (vapor)

That state is called <em>triple point. </em>The conditions necessary for that to occur are:

  • 273.1600 K (0.0100 °C; 32.0180 °F)  as temperature and
  • 611.657 pascals (6.11657 mbar; 0.00603659 atm) as pressure

Cheers

Cheers

8 0
3 years ago
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