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melamori03 [73]
3 years ago
12

A guinea pig was injected with radioactive amino acids. Thirty minutes later, tissue analysis showed that protein of the ribosom

es had over twice as much radioactivity per gram as the protein of any other part of the cell. What can be concluded from this experiment? Why?
Biology
1 answer:
adell [148]3 years ago
5 0

Answer:

Mutation occurs.

Explanation:

Mutation occurs in the tissues that receives radiations because the production of proteins by ribosomes increases. In normal conditions, ribosomes produces normal amount of protein but in this case proteins production increases by the tissue due to exposure to radioactive amino acid that causes mutation in the ribosomes and it increases its protein production.

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Which of the following sentences best describes osmosis?
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Answer:

D is the correct Answer

Explanation:

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1) Glycogen phosphorylase catalyzes the removal of glucose from glycogen. The ∆G°’ for this reaction is 3.1 kJ/mole 1. Calculate
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Answer:

1. G° = -RT ln (G1P/P)

3.1 = 8.314 × 310 × ln (G1P/P)

3.1 / 2577.34 = ln (G1P/P)

0.0012 = ln (G1P/P)

0.0012 = (log G1P/P)/log 2.71828

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Another merit of phosphorylated glucose is that it comprises the negative charge and cannot diffuse out of the muscle cell. Thus, the reaction will not be at equilibrium under the physiological conditions and always encourages the generation of the products. The formation of products will amend the change in free energy in such a manner that the reaction will always carry in the forward direction.  

3. Greater the ratio of [Pi]/[glucose-1-phosphate], higher will be the relative rate of glycogen phosphorylase in comparison to the phosphoglucomutase as the transformation of Glu-1-P becomes slow because of lesser accessibility of substrate.  

4 0
3 years ago
When organisms reproduce sexually, the species number of chromosomes 1
Zanzabum

Answer:

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My name is Ann [436]
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DochEvi [55]

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