The slopes of 2 perpendicular lines with be reciprocals with the opposite sign.
For example if you have the equation y=-5x+2, your slope is -5. In a line perpendicular to y=-5x+2, your slope would be 1/5. As for finding b in y=mx+b for your second equation, I would need more specific information.
Hope it helps!
<h2>Answer</h2>
<h2>Explanation</h2>
Remember that the square root function is not defined, in the set of real numbers, for negatives values, so its radicand (the thing inside the square root) must be zero or bigger than zero. In other words, to find the domain of a square root function, you should set the thing inside the radical bigger or equal to zero and solve for x. Let's find the domain of each one of our functions:
For
The thing inside the square root is 
, so we are setting that bigger or equal than zero and solve for x to find the domain of the function:
domain
For 
domain
For 
and 
domain
As you can see, the only one that has the domain is the first choice.
Answer:
y = 2x - 3
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = 2, thus
y = 2x + c ← is the partial equation of the line
To find c substitute (2, 1) into the partial equation
1 = 4 + c ⇒ c = 1 - 4 = - 3
y = 2x - 3 ← equation of line
Answer:
The answer is 1/9.
Step-by-step explanation:
Using the equation a-b=2, we can solve that a = 2+b.
We can then <u>substitute that into the expression</u> given to get 3^b/3^(2+b).
Since <u>they have the same base, we can subtract the exponents from the numerator and denominator</u> to get 3^(b-2-b) which <em>simplifies to 3^-2.</em>
3^-2 is simply 1/9.
