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aliina [53]
3 years ago
8

.

Mathematics
2 answers:
sergeinik [125]3 years ago
6 0

Answer:Your answer is a c and f

Juli2301 [7.4K]3 years ago
4 0

Answer:

the answer is......

Step-by-step explanation:

f ,c,a

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david a high school senior was wondering if the cost of attending college is worth the expense. he collected the following data
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Part A: Based on the information collected, who will have the higher mean annual salary?  

College graduates have a higher mean by about $20,000

 

Part B: If you were to graph this data, what would be important to consider?  

The data should be graphed on the same axis and scale so comparisons are possible

Step-by-step explanation:

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and btw go easy on his injury cowboys! till i die

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The kind of dreams where you wake up and can’t stop smiling.

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Isabella earns $48.75 for 5 hours of babysitting. At this rate, how much more would she earn for 11 hours of babysitting?
MAVERICK [17]
She would earn $107.25
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D
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Step-by-step explanation:

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If f(x) = 9x10 tan−1x, find f '(x).
djverab [1.8K]

Answer:

\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)  

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                             \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = 9x^{10} \tan^{-1}(x)

<u>Step 2: Differentiate</u>

  1. [Function] Derivative Rule [Product Rule]:                                                   \displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  2. Rewrite [Derivative Property - Multiplied Constant]:                                  \displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  3. Basic Power Rule:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  4. Arctrig Derivative:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
3 years ago
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