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3 years ago

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Mathematics

2 answers:

sergeinik [125]3 years ago

6 0

Answer:Your answer is a c and f

Juli2301 [7.4K]3 years ago

4 0

Answer:

the answer is......

Step-by-step explanation:

f ,c,a

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Solve the equation, and check the solution. 1/3s =1/5

Vaselesa [24]

Answer:

3/5

Step-by-step explanation:

1/3s=1/5

s=(1/5)/(1/3)

s=(1/5)(3/1)

s=3/5

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3 years ago

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Find the missing side of the triangle and leave the answer in simplest radical form.

tatuchka [14]

Answer:

x = $\sqrt5$

Step-by-step explanation:

Using Pythagoras theorem,

Square of longer side = Sum of square of other sides .

Therefore,

$(\sqrt{11})^2 = x^2 + (\sqrt{6})^2\\\\11 = x^2 + 6\\\\11 - 6 = x^2\\\\5 = x^2\\\\x = \sqrt 5$

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3 years ago

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Step-by-step explanation:

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3 years ago

Four lines are shown in the graph below.

Vikki [24]

Answer:

Step-by-step explanation:

A vertical line will have the steepest slope

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2 years ago

iren2701 [21]

Answer:

Step-by-step explanation:

Given:

A. $2x^3-x^{2} -6x$

B. $2x^3+8x+4$

C. $3x^4+x^{2} +x-7$

D. $3x^4-3x^{2} +5x-7$

Now, let us evaluate the given expressions one by one.

$(4x^3-4+ 7x)-(2x^3-x-8)\\\Rightarrow 4x^3-4+ 7x-2x^3+x+8\\\Rightarrow 2x^3+8x+ 4$

It is equation B.

So, $(4x^3-4+ 7x)-(2x^3-x-8)$ is equivalent to B.

$(-3x^2+x^4+x)+(2x^4-7+4x)\\\Rightarrow -3x^2+x^4+x+2x^4-7+4x\\\Rightarrow3x^4-3x^{2} +5x-7$

It is equation D.

So, $(-3x^2+x^4+x)+(2x^4-7+4x)$ is equivalent to D.

$(x^{2} -2x)(2x+3)\\\Rightarrow 2x^3-4x^{2} +3x^{2} -6x\\\Rightarrow 2x^3-x^{2} -6x$

It is equation A.

So, $(x^{2} -2x)(2x+3)$ is equivalent to A.

So, answer is:

8 0

3 years ago