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vfiekz [6]
3 years ago
5

The total cost of a ticket and the online fee for one ticket is $32.25.Let f represent the cost of ordering each ticket online.W

rite an equation that could be used to find the cost of ordering each ticket online.
Mathematics
1 answer:
Bezzdna [24]3 years ago
8 0

Answer:

The equation is f = z - x

Step-by-step explanation:

The equation is

Given that

The total cost + online fee for one ticket is $32.25

Let us assume f be the cost of ordering each ticket online

Cost of each ticket be x = $24.95

And, the total cost = z = $32.25

Now the equation would be

x + f = z

So for f it would be

f = z - x

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It takes Jack Frost 5 minutes to fly 35 minutes with the wind. It takes him 7 minutes to go 35 minutes against the wind. Determi
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Answer:his speed in still air is 6 miles per minute.

the speed of the wind is 1 mile per minute.

Step-by-step explanation:

Let x represent his speed in still air.

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Distance = speed × time

It means that

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35 = 5x + 5y - - - - - - - - - - -1

It takes him 7 minutes to go 35 miles against the wind. This means that his total speed would be x - y

It means that

35 = 7(x - y)

35 = 7x - 7y - - - - - - - - - - -2

Multiplying equation 1 by 7 and equation 2 by 5, it becomes

245 = 35x + 35y

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Adding both equations, it becomes

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x = 420/70 = 6

Substituting x = 6 into equation 1, it becomes

35 = 5 × 6 + 5y

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y = 5/5 = 1

5 0
4 years ago
Evaluate the expression 21 ÷ 3 + 8 − 4.<br><br> A) 19<br><br> B) 17<br><br> C) 15<br><br> D) 11
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2 years ago
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lys-0071 [83]

\displaystyle&#10;(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k

<em>-------------------------------------------------------------</em>


\displaystyle&#10;(x^2+y)^n=\sum_{k=0}^n\binom{n}{k}x^{2n-2k}y^k\\&#10;n=5\\&#10;k=3\\\\\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdor5}{2}=10

<u>It's 10.</u>

----------------------------------------------------

\displaystyle&#10;(3x^2+y)^n=\sum_{k=0}^n\binom{n}{k}(3x)^{2n-2k}y^k=\sum_{k=0}^n\binom{n}{k}\cdot 3^{2n-2k}\cdot x^{2n-2k}y^k\\\\&#10;n=5\\&#10;k=4\\\\&#10;\binom{5}{3}\cdot3^{2\cdot5-2\cdot4}=10\cdot3^{2}=10\cdot9=90

<u>It's 90</u>

6 0
4 years ago
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