Question

Assume 10% of Berkeley students are left-handed. If you are in a class of 50 people, what is the probability that exactly 4 of them are left-handed? Round your answer to the nearest hundredth, and omit the leading zero. Enter your answer here.

Answer 1

Answer:

The answer is "0.18"

Step-by-step explanation:

$10\% \ of \ 50= 5 \text{are left handed}\\\\45\ \text{are right handed}$

If the probability exactly 4 were heft handed

 $=^{50}_{C_4}\times (\frac{5}{50})^4 \times (\frac{45}{50})^{4b}\\\\=^{50}_{C_4} \times (0.1)^4 \times (0.9)^{4b}\\\\=230300 \times (0.1)^4 \times (0.9)^{4b}\\\\=0.181 \approx 0.18$