Answer: 
Step-by-step explanation:
Since, The total number of student = 300
Out of which,
The number of students who are only in Maths = 120
And, The number of students who are only in Science = 50
While, the students who are not from any subject = 100
Hence, the number of student who are from both maths and science = Total student - Maths student (only) - science student (only) - None
= 300 - 120 - 50 - 100
= 30
That is, there are 30 students who are both from science and maths,
Thus, the probability of selecting one student who is both from maths and science = 30/300 = 1/10
We know that
∠X≈∠B
∠Y≈∠C
∠Z≈∠A
XZ≈BA
XZ=12
BA=9
XY≈BC
XY=14
BC=10.5
ZY≈AC
ZY=16
AC=12
the scale factor=12/16-----> 0.75
therefore
the answer is the option D
Answer:
12
Step-by-step explanation:
Answer:
The first and second one
Step-by-step explanation:
4(m-5)=4*m-4*5=4m-20
2(2m-10)=2*2m-2*10=4m-20