Answer:
We have function,

Standard Form of Sinusoid is

Which corresponds to

where a is the amplitude
2pi/b is the period
c is phase shift
d is vertical shift or midline.
In the equation equation, we must factor out 2 so we get

Also remeber a and b is always positive
So now let answer the questions.
a. The period is


So the period is pi radians.
b. Amplitude is

Amplitude is 6.
c. Domain of a sinusoid is all reals. Here that stays the same. Range of a sinusoid is [-a+c, a-c]. Put the least number first, and the greatest next.
So using that<em> rule, our range is [6+3, -6+3]= [9,-3] So our range</em> is [-3,9].
D. Plug in 0 for x.





So the y intercept is (0,-3)
E. To find phase shift, set x-c=0 to solve for phase shift.


Negative means to the left, so the phase shift is pi/4 units to the left.
f. Period is PI, so use interval [0,2pi].
Look at the graph above,
I believe the most logical answer would be is to divide so us the kcf method keep change flip so 5 stays the same then change division into multiplication then flip the fraction 1/3 into 3/1 so now we have 5 times 3 is 15
Let

be the number of hours that the waitress works in the evening.
We know for our problem that she works

in the afternoon and that she works <span>1.75 hours less in the afternoon than in the evening, so:
</span>

<span>Since </span>

, we can rewrite our expression:


We can conclude that she works 3.375 hours in the evening, or expressed as a mixed fraction:

hours.
Answer:
The first one should be right. Since the teacher is charging $15 per hour of the piano lesson then it can't be any of the answers of $100h. The answer can't be C, the third one, since you're adding the enrollment fee to the cost of every piano lesson it would be wrong to subtract the $100. Hope that helps!
Step-by-step explanation:
The answer will the answer on the top $25=$100+$15h over h
Answer:
8
Step-by-step explanation: