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grandymaker [24]
2 years ago
10

G identify which substitution product is expected to be favored. explain. the product with retention of configuration is expecte

d to predominate slightly, because the leaving group blocks the nucleophile. the inverted product is expected to predominate slightly, due to sn2 competition. the inverted product is expected to predominate slightly, as a result of ion pairs. the product with retention of configuration is expected to predominate slightly, because the leaving group attracts the nucleophile.
Chemistry
1 answer:
ddd [48]2 years ago
4 0

The substitution product that is supposed to be favoured. The product with retention of configuration is expected to predominate slightly because the leaving group blocks the nucleophile.

<h3>What is a substitution product?</h3>

A substitution product is a product that is gotten from a reaction in which a group of reactants is replaced by another group in the reaction.

Therefore, the substitution product is supposed to be favoured. The product with retention of configuration is expected to predominate slightly because the leaving group blocks the nucleophile.

Learn more about substitution reaction below.

brainly.com/question/10143438

#SPJ1

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If you have 120. mL of a 0.100 M TES buffer at pH 7.55 and you add 3.00 mL of 1.00 M HCl, what will be the new pH? (The pKa of T
Simora [160]

Answer:

The new pH after adding HCl is 7.07

Explanation:

The formula for calculating pH of a buffer is

pH = pKa + log([Conjugate base]/[Acid])

<u>Before adding HCl,</u>

         7.55 = 7.55 + log([Conjugate base]/[Acid])

⇔      log([Conjugate base]/[Acid])  = 0

⇔     [Conjugate base] = [Acid] = 1/2 x 0.100 = 0.05 M

⇒ Mole of Conjugate base = Mole of Acid = 0.05 M x 0.12 mL = 0.006 mol

<u>After adding HCl (3.00 mL, 1.00 M)</u>

⇒ Mole of HCl = 0.003 x 1 = 0.003 mol)

New volume solution is 120 m L+ 3 mL = 123 mL

HCl is a strong acid, it will convert the conjugate base to acid form, or we can express

Mole of new Conjugate base = 0.006 - 0.003 = 0.003 mol

                ⇒ Concentration = 0.003/0.123 M

Mole of new Acid form = 0.006 + 0.003 = 0.009 mol

                ⇒ Concentration = 0.009/0.123 M

Use the formula

pH = pKa + log([Conjugate base]/[Acid])

    = 7.55 + log(0.003 / 0.009) = 7.07

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Assume a gasoline is isooctane, which has a density of 0.692 g/ml. What is the mass of 3.8 gal of the gasoline (1 gal = 3.78 l)?
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The mathematical expression is given as:

density=\frac{mass}{volume}

Now, density of isooctane = 0.692 g/mL

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Since, 1 gallon = 3.78 L

So, 3.8 gal = 3.78 L\times 3.8

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As, 1 L = 1000 mL

Therefore, 14.364 L= 14.364 L\times 1000 mL

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Put the values,

0.692 g/mL=\frac{mass}{14364 mL}

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harkovskaia [24]

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